49 g Incorrect Question 45 Which of the following sugars is the enantiomer of D-glucose? CHO H -OH HO H D-glucose H -OH H -OH CH₂OH 0/2.5 pts CHO CHO CHO CHO CHO ht H OH H -OH H -OH HO H HO -H HO H HO H H OH H -OH H -OH H -OH H -OH HO -H HO -H HO H H- -OH HO H H- -OH HO H H-OH CH2OH CH₂OH CH₂OH CH₂OH CH2OH a. b. C. d. e. sugar c sugar b sugar d sugar e sugar a

49 g Incorrect Question 45 Which of the following sugars is the enantiomer of D-glucose? CHO H -OH HO H D-glucose H -OH H -OH CH₂OH 0/2.5 pts CHO CHO CHO CHO CHO ht H OH H -OH H -OH HO H HO -H HO H HO H H OH H -OH H -OH H -OH H -OH HO -H HO -H HO H H- -OH HO H H- -OH HO H H-OH CH2OH CH₂OH CH₂OH CH₂OH CH2OH a. b. C. d. e. sugar c sugar b sugar d sugar e sugar a

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter20: Carbohydrates

Section: Chapter Questions

Problem 20.14P

See similar textbooks

Similar questions

N-NHPH CHO CH2OH H- C=N-NHPH Но- -H- 3 equiv Но- -H- 3 equiv Но- PHNHNH2 PHNHNH, H- H- OH H- -O- H- H- -HO- H- -HO- ČH2OH ČH2OH ČH2OH D-glucose osazone D-fructose + NH3 + PHNH2 + 2 H20 The final step in the formation of the osazone from glucose is the reaction of the keto imine with 2 equivalents of phenylhydrazine to yield the osazone plus ammonia. This reaction involves the following intermediate steps: 1. Addition of phenylhydrazine to the imine and proton transfer to yield intermediate 1; 2. Elimination of ammonia to yield phenylhydrazone 2; 3. Addition of phenylhydrazine to the ketone to yield tetrahedral intermediate 3; 4. Proton transfer yields carbinolamine 4; 5. Elimination of water yields the final product osazone. Write out the mechanism on a separate sh of paper and then draw the structure of tetrahedral intermediate 3. NH НО- -H H- -ОН H- -ОН ОН Glucose keto imine Previous Ne
Two sugars differing in configuration at a single asymmetric carbon atom are known as epimers. D-mannose is a C-2 epimer of glucose (Structure I), while D-galactose is a C-4 epimer of glucose. Structure Il and IIl are H- -OH но- -H H OH HO H но- H HO H H -OH H- -OH HO OH H -OH H- -OH H OH HO. HO, OH II II Which of the following represents an aldopentose? OH H O HO O HO H но н HO H но- HO H HO H HO- H OH H OH H OH H OH OH HO Он of но" HO O OH он III IV These are chemical messengers that are secreted by endocrine glands and carried through the bloodstream to target tissues. prostaglandin deoxysugar glycoside hormones Which of the following is NOT correctly paired? cellulose: beta-1,4-glycosidic linkage amylose: alpha-1,4-glycosidic linkage chitosan: alpha-1,4-glycosidic linkage cellubiose: beta-1,4-glycosidic linkage
7. Draw the Haworth structure for the following monosaccharides a. H НО H c=0 H + но - н 3 4 Н 5 - ОН - OH 애 CH₂OH 6 D-Mannose b. H 0 = с H - C - OH HO-C - H H - C - OH H - C - ОН CH₂OH Glucose
The enatiomer of D-sorbose: CH₂OH C: =0 H HO- H OH -H -OH CH₂OH D-sorbose Select one: Is an L-sugar that has opposite configuration around one carbon. Is an L-sugar that has opposite configuration around three carbons. Is a D-sugar that has opposite configuration around three carbons. Is a D-sugar that has opposite configuration around one carbon.
Classify the structures as being either an enantiomer, diastereomer or diastereomer/epimer of D-glucose. Structure A: CH H- -OH Structure B: но- H- H- OH Structure C: H- он H- -H D-Glucose: OH || CH CH CH он H- он но -H H- он но он но но- H- но H- OH OH но -- H- -H H -Ç-H Structure A: OH Structure B: OH Structure C: OH
Maltose is the most common disaccharide that consists of two (2) glucose monomers. What is the glycosidic linkage between the two monomers in maltose? O a-1,4 glycosidic, a-(1-4) O B-1,4 glycosidic, B-(1-4) a-1,6 glycosidic, a-(1-6) O B-1,6 glycosidic, B-(1-6) O a-1,0-1 glycosidic, a,a-(1-1)
Which of these sugars are epimers of D-Fructose? CH₂OH CH₂OH CH₂OH НО Н Н A B CH₂OH D-Fructose C Н D -OH -OH HO Н HO 20 -Н H OH HO H HỌ CH₂OH A 0 OH H H H Н Н- CH₂OH B CH₂OH OH H- -OH HO OH H CH₂OH с CH₂OH =0 -OH I -H OH CH.OH D
What is the relationship between these two sugars? H- HO HO CH₂OH OH ∙H -H CH₂OH A) identical structures B) enantiomers C) diastereomers D) constitutional isomers E) non-isomeric H- H- H- CH₂OH -OH -OH -OH CH₂OH
The image shows Fischer projections for the structures of four isomers of a ketopentose. CH₂OH CH₂OH CH₂OH ПА пс C=O D HOEC H HOECH CH,OH A C=O H➡ COH но-с-н CH₂OH Which of the structures are stereoisomers of B? B Which of the structures are diastereomers of D? C=O HOI-C-H HOI-C-H CH₂OH с 000 ΤΑ B HO D CH₂OH O Which of the structures are enantiomers of C? H HI COH D CH₂OH
What is the relationship between the following monosaccharides? Osc O= Но- H. H- ОН Но H FOH ОН Но- H HO. Но- ČH2OH ČH2OH enantiomers O completely different O epimers diastereomers エエ I I エエ

O- alpha (1->4) ОН The name of this disaccharide is ribofuranose CH2OH It is a non-reducing ОН + ОН - -D- glucopyranosyl alpha sugar. CH2OH ОН ОН - -D-
18-52 Classify cach of the following monosaccharides as an aldose or a ketose. CHO HO-C-H ÇH,OH re-ee HO'H C=0 HO-C-H HO-C-H HO-C-H HO-C-H H-C-OH CH;OH CH;OH с. CHO d. CH;OH HO-C-H C=0 H-C-OH HO-C-H CH,OH HO-Ć-H H-C-OH 18 CH;OH 18-53 Classif