Solve for the unknown values in table 3 and 4 in handwriting. Thanks. of the £ourthe length ofMEASUREMBNTS. Foreachtraverses3. OMITTEDgiven in the accompanying tabulations ,side and the bearing (or azimuth) of an adjoining sideunknown. Determine these unknown quantities.oneazeDISTANCEAZIMUTHLENGTHCOURSESIDEBEARING( m)IFROM SOUTH(m)的2.50248.78ABDue EostUnknowa,75°00'{-2269.90$89°26'ES27° 43'W2-3Unknown199.88CDUnknown,225 24297 26'274.76DE220.42UmiknownEA443.49N40°08'w245.64LENGTHDISTANCEAZIMUTHSIDEBEARINGLINE(m)(m)FROM NORTH334 27'NO9°30'wN55 * 06'W$57 35'Ws04 05'EAB413.60UnknewnBC304.38955.00Unknownro5 30'193° 44'250°05'CD407.21,594.72DEUnknown874.23E A649.63Unknown7|1.50

Given : Table-3 : Side Length, L (m) Bearing, θ Lattitude, Lcosθ Departure,…

3. OMITTED MEASUREMENTS. For given side and the bearing (or azinuth) of an adjoining side unknown. Determine these unknown quantities. each of the four traverses in the accompanying tabulations, the length of one aze LENGTH DISTANCE ( m) AZIMUTH SIDE BEARING COURSE (m) FROM SOUUTH 382.50 248.78 {-2 269.90 Unknowa AB Due Eest $88°26'E s27° 43'w 2-3 Unknewn 75°00' 199.88 CD Unknown, 225°24 297°26' 274.76 DE 220.42 Unisaown 5 -- ! EA 443.49 N40°08'w 245.84 LENGTH DISTANCE AZIMUTH SIDE BEARING LINE (m) (m) FROM NORTH 334°27' NO9 30'w N55 *06'w $57 35'w so4°05'E AB 413.60 |- 2 Unkaown BC 304.38 Unknown 2- 3 3- 4 955.95 ro5 30' 193° 44' 250°05' CD 407.21 594.72 DE Unknown 4- 5 874.23 E A 649.63 Unknown 5 - ! 711.50

3. OMITTED MEASUREMENTS. For given side and the bearing (or azinuth) of an adjoining side unknown. Determine these unknown quantities. each of the four traverses in the accompanying tabulations, the length of one aze LENGTH DISTANCE ( m) AZIMUTH SIDE BEARING COURSE (m) FROM SOUUTH 382.50 248.78 {-2 269.90 Unknowa AB Due Eest $88°26'E s27° 43'w 2-3 Unknewn 75°00' 199.88 CD Unknown, 225°24 297°26' 274.76 DE 220.42 Unisaown 5 -- ! EA 443.49 N40°08'w 245.84 LENGTH DISTANCE AZIMUTH SIDE BEARING LINE (m) (m) FROM NORTH 334°27' NO9 30'w N55 *06'w $57 35'w so4°05'E AB 413.60 |- 2 Unkaown BC 304.38 Unknown 2- 3 3- 4 955.95 ro5 30' 193° 44' 250°05' CD 407.21 594.72 DE Unknown 4- 5 874.23 E A 649.63 Unknown 5 - ! 711.50

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

7.4 MADE L Fazit On en Colerdo P the an ◄AYAY AT----- TP. TUTT the pre VIVIAVI Det ty ita obo y Survey e fue The courthouse record for a 1902 property survey at Ketchikan, Alaska, lists the magnetic direction of a property boundary as S82°44'W. If the 1902 declination was 37°08'E and the present declination is 26°17'E, find the true bearing and the present magnetic bearing of the property line.
Help me pls i give upvotee33e
50lve the FolHowing differee differentiat equations
help me pls, igive you upvote
2. The buildine is to be constructed on a lot shown below. Calculate the distances of lines (1-2) and (6-7). 9 S70 21'50 E N64 25 41E 8 49.794 50.495 10 N86 52' 22"W |2 1 7 3 S54 50 45°E 56.321 4 S68 13 05 W 46.744 6. N66° 52 5TW 48.0 17 N18° 55'42"E 43.052 M.6V 10 .91N S3° 22' 11"W w 32.107 5 25.818
A * SHOW CALLATñONS By SKETCHINIG IFLIENCE LINE IFL Jusi To RIGHT OF G
Find noemel stres at pointA ? たたん

8 Convert 2341 Greek Units to Feet 2367.336 ft 3459.486 ft O2458.349 ft 3277.461 ft 3177.348 ft 2440.146 ft None of the Choices
(a) Briefly explain the main reason the used of transition curves, how the transition curve is used in road geometry design and the purpose of super-elevation in combine road curve design. Q3. (b) Two straights, Al and IB, whose bearings are DDD° AI' Al" and DDD° IB' IB" respectively intersect at point I, are to be connected by a combined curve. The chainage of point / is CCCC m, while the design speed and radius have been fixed at 90 km/h and 550 m respectively. Adopting a rate of change of acceleration of 0.3 m/s. As a civil engineer have been assign to do a trial analysis of the proposed design of horizontal combine curve (T1, T2, T3 and T4) and prepared road curve setting-out data (T1 to T2, T2 to T3, T3 to T4) at 20 m intervals using deflection angle and chord distance method. (c) By adopting the coordinate of intersection point / as (YYYY N, XXXX E). Calculate the coordinate of tangent point for T1, T2, T3 and T4.
y } C 1 t B 3. A. 5O
ANSWER KEY:Elev Sta. B= 700.3994mElev Sta. C= 243.2945m∆hAB= 458.8394m∆hBC= 457.1049m∆hCA =1.7345mthese are the exact answer, please show the right solution. Thankyou :)
$75 15'E 708.35 m Figure 5 Unknown Length S86 35 W 607.66 m Determine: Length of Line DE Bearing of Line FA Draw the new traverse showing a new cut line for Omitted Measurement Case 3 ( Buueag 404.10 m Unknown N42 SO'W 677.73 m $31'35'W w 80 TOE