need soon both 3) Consider the titration of 40.0 mL of 0.100 M maleic acid (H2M) with 0.200 M NAOH.Maleic acid is diprotic with Kal = 1.20 x 10 2 and Ka2 = 5.96 x 107. At volumes in the titrationthat are between the first and second equivalence points, the solution can best be described ascontaininga) a buffer of H2M and HM.b) a buffer of HM and M2.c) HM.d) M.e) M and excess NaOH.%3Db. Consider the titration of 40.0 mL of 0.100 M maleic acid (H2M) with 0.200 M NAOH.Maleic acid is diprotic with Kal 1.20 x 102 and K2 5.96 x 107, When 12.0 mL of theNaOH solution has been added, what of the concentration of H2M that is plugged into theappropriate K. expression in order to calçulate [H3O]?a) 0.0320 Mb) 0.100 Mc) 0.128 Md) 0.0480 Me) 0.0400 M

Given: Volume of maleic acid i.e. H2M = 40.0 mL = 0.040 L (Since 1 L =…

3) Consider the titration of 40.0 mL of 0.100 M maleic acid (HzM) with 0.200 M NaOH. Maleic acid is diprotic with Kal 1.20 x 102 and Ka2 = 5.96 x 107. At volumes in the titration that are between the first and second equivalence points, the solution can best be described as containing a) a buffer of H2M and HM. b) a buffer of HM and M2. c) HM. d) M. c) M and excess NaOH. b. Consider the titration of 40.0 mL of 0.100 M maleic acid (H2M) with 0.200 M NaOH. Maleic acid is diprotic with Kal 1.20 x 102 and Ka2 5.96 x 107, When 12.0 mL of the NaOH solution has been added, what of the concentration of H2M that is plugged into the appropriate K. expression in order to calçulate [H3O'] ? a) 0.0320 M b) 0.100 M c) 0.128 M d) 0.0480 M e) 0.0400 M %!

3) Consider the titration of 40.0 mL of 0.100 M maleic acid (HzM) with 0.200 M NaOH. Maleic acid is diprotic with Kal 1.20 x 102 and Ka2 = 5.96 x 107. At volumes in the titration that are between the first and second equivalence points, the solution can best be described as containing a) a buffer of H2M and HM. b) a buffer of HM and M2. c) HM. d) M. c) M and excess NaOH. b. Consider the titration of 40.0 mL of 0.100 M maleic acid (H2M) with 0.200 M NaOH. Maleic acid is diprotic with Kal 1.20 x 102 and Ka2 5.96 x 107, When 12.0 mL of the NaOH solution has been added, what of the concentration of H2M that is plugged into the appropriate K. expression in order to calçulate [H3O'] ? a) 0.0320 M b) 0.100 M c) 0.128 M d) 0.0480 M e) 0.0400 M %!

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter15: Additional Aqueous Equilibria

Section: Chapter Questions

Problem 93QRT: When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence...

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