q11 T(20 + log t,)(°R-h)Larson-Miller parameter :12. 10° (R-h)253035404550х103х103х103х103х103 х103Larson-Miller parameter =100,000 |2.2. 10° (K-h)Stress = 6.9 MPA%3DStress = 1· 10³ psi10010,00010100012x10316202428х103х103х103х103T(20 + log t,)(K-h)Stress (MPa)Stress (psi) For an 18-8 Mo stainless steel (Animated Figure 8.36), predict the time to rupture for a component that is subjected to a stressof 80 MPa (11,600 psi) at 700°C (973 K).ihours

stress=80MPa(11600psi)Temperaure=700°C(973k) To-Find:- Time to rupture =.................hours

Answered: 25 30 35 40 45 50 |12. 10° (R-h) х103…

Engineering

Mechanical Engineering

25 30 35 40 45 50 |12. 10° (R-h) х103 х103 х103 х103 х103 х103 Larson-Miller 100,000 |2.2- 10° (K-Һ)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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