2. Using the t-distribution table in Appendix 2, with a significance level a = 0.05, determine the suitable critical value for conducting the hypothesis test for the Elie's research. Appendix 2 One-tailed test 1 t Two-tailed test df 0.1 0.05 0.025 0.02 0.01 99 1.2902 1.6604 1.9842 2.0812 2.3646 100 1.2901 1.6602 1.9840 2.0809 2.3642 101 1.2900 1.6601 1.9837 2.0806 2.3638
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- What is meant by the sample space of an experiment?Examus cdn.studentuae.examus.netridban3D1&sessi... Choose the correct answer for the following question: A simple random sample of front-seat occupants involved in car crashes is obtained. Among 1550 occupants not wearing seat belts, 12 were killed. Among 6500 occupants wearing seat belts, 12 were killed. Using this data with 0.05 significance level to test the claim that the fatality rate is higher for those not wearing seat belts, the alternative hypothesis is given as ct912 10 a. 362 b. H:P1 SP2 C. Hj: p P2 cf917 d. Hj: p>P2 ce362dcf917 ce362dct917 ce3624ci917 362dcf917 ce362acf917 ce362dcf917 0% ce362dcf917 MacBook Pro 7. e362dcf917 C0 P.Use a 0.05 significance level to test the claim that the different samples come from populations with the same mean. Use the traditional method. List the null and alternative hypothesis, the critical value, the test statistic, Draw the graph and label the test statistic, critical value and rejection regions. Reject or fail to reject? State the conclusion as outlined in the template or book Your hypothesis test must take up one whole page only (8 1/2" x 11"), typed or written and must be neat. ANOVA Source of Variation SS df MS F P-value Factor 13.500 3 4.500 5.171 0.0011 Error 13.925 16 0.870 Total 27.425 19
- 22. For a one-tailed test (lower tail) with a sample size of 10 and a .10 level of significance, the critical t value is -1.383 -2.821 -1.372 1.383In a camping group, two groups of campers were considered and their scores were recorded. We are using a 0.05 significance level to test the claim that students of group 2 have a higher mean than those of group 1. Group 1 n = 40, sample mean = 78.40, sample standard deviation = 12.87 Group 2 n = 34, sample mean = 81.62, sample standard deviation = 22.09 what is error and CIA power supply company states that it has a target power supply of 119 volts. A researcher wants to test the company’s claim so she collected data from 30 random family homes and calculated the following sample statistics: Sample Mean = 118.89 volts, s= 0.35 volts . Use a 0.01 significance level to test the claim that the mean power supply is 119 volts. 1) Identify the null and alterative hypotheses, test statistic, and P-value. Round to three decimal places.
- If a sample of 50 individuals was taken from a population with a standard deviation of 12 and the sample mean is 95, what is the t-statistic for a two-tailed hypothesis test at a significance level of 0.05?You wish to test the following daim (Ha) at a significance level of a = 0.005. H.:P1 > P2 Ha:P1 < P2 You obtain a sample from the first population with 303 successes and 238 failures. You obtain a sample from the second population with 155 successes and 79 failures. critical value = [three decimal accuracy] test statistic = [three decimal accuracy] The test statistic is... O in the critical region O not in the critical region This test statistic leads to a decision to... reject the null hypothesis fail to reject the null hypothesis As such, the final condusion is that... O There is sufficient evidence to support that the first population proportion is less than the second population proportion. O There is not sufficient evidence to support that the first population proportion is less than the second population proportion.c) Check whether the assumptions of normality and variance equality are satisfied for part b of this question. Use a nonparametric test and compare your finding with that from part b. Use the residuals from the ANOVA test and include Q-Q plot and Boxplot.
- If we have a sample of size 100 with sample mean breaking strength of 975 pounds from a population of rope with standard deviation 200 pounds and we wish to run a hypothesis test with this data to see if the population mean breaking strength differs from 1000 pounds, what is the P-value of our data?A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed? populations, and do not assume that the population standard deviations are equal. Complete parts? (a) and (b) below. Use a 0.10 significance level for both parts a)what is the null and alternative hypothesis? (m1 treatment)=n=31,x=2.32,s=.98 (m2 placebo)=n=34, x=2.69, s=.54 a)Test the claim that the two samples are from populations with the same mean.What are the null and alternative? hypotheses? b)what is the test statistics, and p-value? c) Construct a confidence interval suitable for testing the claim that the two samples are from populations with the same mean. do we reject or fail to rejectThe z-statistic for the difference between the tvlo sample proportions is 5.266 with a P- value of 0.00000014. What conclusion could you make about the difference between the two population proportions if the level of significance is set to 0.05? O The difference is not statistically significant because the sample proportion difference of 0.05 is equal to the significance level of 0.05 The difference is statistically significant because the P-value of 0.00000014 is less than the significance level of 0.05. O The difference is statistically significant because the z-statistic of 5.266 is greater than the significance level of 0.05. O The difference is not statistically significant because the significance level of 0.05 is greater than the P-value of 0.00000014.