2. Uniparental disomy is a rare phenomenon in whichonly one of the parents of a child with a recessivedisorder is a carrier for that trait; the other parent ishomozygous normal. By analyzing DNA polymorphisms, it is clear that the child received both mutantalleles from the carrier parent but did not receive anycopy of the gene from the other parent.a. Diagram at least two ways in which uniparentaldisomy could arise. (Hint: These mechanismsall require more than one error in cell division,explaining why uniparental disomy is so rare.)Is there any way to distinguish between thesemechanisms to explain any particular case ofuniparental disomy?

2. Uniparental disomy is a rare phenomenon in whichonly one of the parents of a child with a recessivedisorder is a carrier for that trait; the other parent ishomozygous normal. By analyzing DNA polymorphisms, it is clear that the child received both mutantalleles from the carrier parent but did not receive anycopy of the gene from the other parent.a. Diagram at least two ways in which uniparentaldisomy could arise. (Hint: These mechanismsall require more than one error in cell division,explaining why uniparental disomy is so rare.)Is there any way to distinguish between thesemechanisms to explain any particular case ofuniparental disomy?

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Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter19: Introduction To Genetics

Section: Chapter Questions

Problem 9CT

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2. Uniparental disomy is a rare phenomenon in whichonly one of the parents of a child with a recessivedisorder is a carrier for that trait; the other parent ishomozygous normal. By analyzing DNA polymorphisms, it is clear that the child received both mutantalleles from the carrier parent but did not receive anycopy of the gene from the other parent.a. Diagram at least two ways in which uniparentaldisomy could arise. (Hint: These mechanismsall require more than one error in cell division,explaining why uniparental disomy is so rare.)Is there any way to distinguish between thesemechanisms to explain any particular case ofuniparental disomy?b. How might the phenomenon of uniparental disomyexplain rare cases in which girls are affected withrare X-linked recessive disorders but have unaffectedfathers, or other cases in which an X-linked recessive disorder is transmitted from father to son?c. If you were a human geneticist and believed oneof your patients had a disease syndrome caused…
1. Hair or fur length in cats is controlled by a single, autosomal gene; the short hair-allele is dominant to the allele for long hair. Hair color is produced by a different gene which is located on the X chromosome. One allele for this sex-linked gene produces yellow, while an alternate allele produces black fur color; individualswhich are heterozygous for these alleles are calico or tortiseshell in color.If a long-haired, black male is mated with a calico female homozygous for short hair what kind of kittens will be produced in the Ej generation? Give both genotypes and phenotypes; express the genotypes bothsymbolically and in words. Label answers clearly!!
6. A person is simultaneously heterozygous for two autosomal genetic traits. One is a recessive condition foralbinism (alleles A and a); this albinism gene is foundnear the centromere on the long arm of an acrocentricautosome. The other trait is the dominantly inheritedHuntington disease (alleles HD and HD+). TheHuntington gene is located near the telomere of oneof the arms of a metacentric autosome. Draw all copies of the two relevant chromosomes in this person asthey would appear during metaphase of (a) mitosis,(b) meiosis I, and (c) meiosis II. In each figure, labelthe location on every chromatid of the alleles forthese two genes, assuming that no recombinationtakes place.
1. In the pedigree below, Use "A" for the allele associated with the dominant phenotype, and lowercase "a" for the allele associated with the recessive phenotype. Determine what is the most likely mode of inheritance of this disease (whether it is inherited as the result of an autosomal dominant or autosomal recessive trait). Write the most probable genotype for each individual based on the mode of inheritance you have determined. Show how all the partners are crossed and the expected offspring produced (You may use Punnett Square) 1 dró || IV
.Certain forms of human color blindness are inherited as X-linkedrecessive traits. Hemizygous males are color-blind, but heterozygous females are not. However, heterozygous females sometimeshave partial color blindness.A. Discuss why heterozygous females may have partial color blindness.B. Doctors identified an unusual case in which a heterozygousfemale was color-blind in her right eye but had normal colorvision in her left eye. Explain how this might have occurred.
5) Humans who have an abnormally high level of cholesterol are said to suffer from familialhypercholesterolemia.  The gene for this disorder is dominant (C). A man who isheterozygous for familial hypercholesterolemia marries a woman who is homozygousfor the recessive allele. What is the probability that they will have children that sufferfrom this disorder? please draw the puutnet square and also write the parents and gemtaics top the puutnet square thanks
6. The pedigree below traces the inheritance of a particular disorder. Circles are females, squares are males. Shaded symbols are affected with the disorder (NOTE: "half-shaded" symbols are NOT used here, for heterozygous individuals). What is the mode of inheritance of this disorder: is it dominant or recessive? Autosomal or X-linked? What is the genotype of the three numbered individuals? 1 2. 3.
5. The pedigree below traces the inheritance of Albinism, a genetic disorder. Affected individuals, indicated here by the coloured circles and squares, are unable to make a normal amount of melanin, the chemical that is responsible for eye, skin, and hair colour. Does Albinism appear to be caused by a dominant allele or by a recessive allele? Fill in the genotypes of the individuals whose genotypes can be deduced. What genotypes are possible for each of the other individuals? Explain! Naruto Hinata Reiner Asta Hange Mikasa Eren Historia Luffy Nezuko Zenitsu Tanjiro Son Goku
4. In humans, cystic fibrosis and albinism are both inherited as independently assorting autosomal recessive traits. Use fto represent the recessive allele for cystic fibrosis and Ffor the allele for the unaffected condition. Use A to represent the dominant allele for normal melanin man is albino and heterozygous for cystic fibrosis. His wife has the unaffected phenotype for both traits, although her father had cystic fibrosis and a for the recessive allele for albinism. and her mother is albino. 4a. What is the genotype of the wife? 4b. What is the probability that a child of this couple is albino and has cystic fibrosis?
2. Null mutations are valuable genetic resources becausethey allow a researcher to determine what happens to anorganism in the complete absence of a particular protein. However, it is often not a trivial matter to determinewhether a mutation represents the null state of the gene.a. Geneticists sometimes use the following test forthe nullness of an allele in a diploid organism: If theabnormal phenotype seen in a homozygote for theallele is identical to that seen in a heterozygote(where one chromosome carries the allele in question and the homologous chromosome is known tobe completely deleted for the gene) then the alleleis null. What is the underlying rationale for thistest? What limitations might there be in interpreting such a result?
1. Use the diagram of the pedigree above, which shows inheritance of an x-linked recessive trait through a family. Select ALL of the individuals in the pedigree who must be carriers for the trait. E G B C H A
. In mice, the dominant allele Gs of the X-linked geneGreasy produces shiny fur, while the recessive wildtype Gs+ allele determines normal fur. The dominantallele Bhd of the X-linked Broadhead gene causesskeletal abnormalities including broad heads andsnouts, while the recessive wild-type Bhd+ alleleyields normal skeletons. Female mice heterozygousfor the two alleles of both genes were mated withwild-type males. Among 100 male progeny of thiscross, 49 had shiny fur, 48 had skeletal abnormalities,2 had shiny fur and skeletal abnormalities, and 1 waswild type.a. Diagram the cross described and calculate thedistance between the two genes.b. What would have been the results if you hadcounted 100 female progeny of the cross?