2. Simplify F(x, y, z) = summation(2, 3, 4, 6, 7) d(x, y, z) = summation (1, 5) and Draw an all-NAND logic diagram for the simplified function in #2.
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2. Simplify F(x, y, z) = summation(2, 3, 4, 6, 7) d(x, y, z) = summation (1, 5) and Draw an all-NAND logic diagram for the simplified function in #2.
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- Design a 3-bit counter that counts the following sequence: 7,5, 3. 1.0.7, 5. 3, 1, 0, 7. etc. Using the sequential design technique that starts from a state diagram, draw the state table. minimize the logic. and draw the final circuit. The outputs of logic circuit are 2 = Qo Q1. I, = Qo.Qi + Qo.Qi, Io = Qo.Q2, Cont2 = Qj Q2 Cont1 = Qu Q2. Cont0 = Q2 Qo.Q1. h = Qo.Qi + Qo.Q1, Io = Qo Qz Cont2 = Q, Q2 Contl = Qo Q2 Cont0 = Q2 Qo Qı Ij = Qo.Q, + Q».Qı, Io = Qo. Q2. Cont2 = Qj Q2. Contl = Qo.Q2. Cont) = Q2 L = Qo.Qı. I¡ = Q. Qj + Qu Q Io = Qv.Qz Comt2 = Q, Q, Contl = Q Q2 Cont0 = Q2 !! fefsto How much will be per-product cost and thAn X-input exclusive-OR gate and a Y-input exclusive-OR gate (where X=3, Y=4 have their outputs connected to a 2-input exclusive-NORgate. Do the following:a) Draw the logic diagram and analyze the logic expression of the output (in standard SOPform).b) List out all essential prime implicants.Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).
- Q4 A-Design Parallel load/Shift right 4 bit register with LD/SR signal. If LD/SR =1 then register parallel load from D3D2DIDO inputs. If LD/SR =0 then it shifts right. Use standard logic gates and D F-F.Consider the given logic equation below. Draw the logic diagram then simplify it using Boolean Algebra. Draw the logic diagram based on the simplified logic equation. X = A'BC' + A'B'C' + AB'C + AB'C' + A'B'C From the given logic diagram, trace the output using all possible input combination. Give it a conclusion upon completion..Consider two 8-bit inputs, A = $52 and B = $C3 to the arithmetic and logic unit (ALU). Compute R =A + B. Express R in the hexadecimal form $-- : -61 Express N-Z-V-C bits in the form ----:
- Draw the equivalent logic circuit diagram of the following expressions : a. XY = F b. X + Y = F XÝZ = F c. d. XY + XZ = F e. XYZ + XÝZ = FQ (A, B, C) = A̅ .B̅. C +A̅ .B. C + A .B. C̅ + A.B.C Karnaugh function given in the form Using the mapping method, you can use the simplified function separately in terms of minterms and maxterms. obtain. Output functions with AND NOT for minterms and OR for maxters. Install separately with logic doors.1. a. i. Draw the gates required to build a half adder are ii. When simplified with Boolean Algebra (x + y)(x + z) simplifies to : iii. The output of a logic gate is 1 when all its inputs are at logic 0, the gate is either :
- DIGITAL LOGIC DESIGN Are the following addition results Overflow or underflow and why?Problem #04] Using AND and OR gates develop the logic circuit for the Boolean equation shown below. Y =AB(C + DEF) + CE(A + B +F) Problem #05] Using AND and OR gates develop the logic circuit for the Boolean equation shown below. X-A(CD+B)5. Simplify the following function using K-Map and draw logic diagram for that. E(A, B,CD)=Em(0,1,2,3,4,5,7,8,10,11,12,13,14,15)