2. Calculate A H for 4FE0(s) + 02(g) → 2Fe203 (s) based on the reactions: 6FEO (s) + O2 (g) →2FE3O4 (s) AH1 = -3607.2 kJ 4Fe304 (s) + O2 (g)→ 6FE2O3 (s) A H2 = +3408.3 kJ

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Chapter6: Thermochemistry
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Problem 128CWP: Calculate H for the reaction N2H4(l)+O2(g)N2(g)+2H2O(l) given the following data: Equation H(KJ)...
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2. Calculate A H for 4Fe0(s) + 02(g)
2FE203 (s) based on the reactions:
6FEO (s) + O2 (g) →2FE3O4 (s)
AH, = -3607.2 kJ
4FE304 (s) + O2 (g)→ 6FE2O3 (s) AH2 = +3408.3 kJ
Transcribed Image Text:2. Calculate A H for 4Fe0(s) + 02(g) 2FE203 (s) based on the reactions: 6FEO (s) + O2 (g) →2FE3O4 (s) AH, = -3607.2 kJ 4FE304 (s) + O2 (g)→ 6FE2O3 (s) AH2 = +3408.3 kJ
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