Pls help ASAP. Pls help on all and pls provide clear and easy to follow solutions. 18. The electric field 0.50 m from a small sphere with a positive charge of 7.2 × 10-5 ℃ isa.2.6 x 106 N/C [inward]d. 2.9 × 104 N/C [inward]e. 2.6 × 106 N/C [outward]b. 2.9 × 104 N/C [outward]C.1.3 x 106 N/C [outward]19. Two 2.0-kg spheres each carry a charge of 2.0 C. How does FE compare with Fg?a. FE=Fgb. Fg > FEC.d.e.FE>FgIf the charges on the spheres are the same, then Fg > Få, but if the charges are oppositethen FE>Fg.FE and Fg cannot be compared without knowing the distance between the spheres..

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18. The electric field 0.50 m from a small sphere with a positive charge of 7.2 x 10-5 ℃ is a. 2.6 x 106 N/C [inward] d. 2.9 x 104 N/C [inward] b. 2.9 x 104 N/C [outward] e. 2.6 × 106 N/C [outward] C. 1.3 x 106 N/C [outward]

18. The electric field 0.50 m from a small sphere with a positive charge of 7.2 x 10-5 ℃ is a. 2.6 x 106 N/C [inward] d. 2.9 x 104 N/C [inward] b. 2.9 x 104 N/C [outward] e. 2.6 × 106 N/C [outward] C. 1.3 x 106 N/C [outward]

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 15P

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Pls help ASAP. Pls help on all and pls provide clear and easy to follow solutions.

18. The electric field 0.50 m from a small sphere with a positive charge of 7.2 × 10-5 ℃ is
a.
2.6 x 106 N/C [inward]
d. 2.9 × 104 N/C [inward]
e. 2.6 × 106 N/C [outward]
b. 2.9 × 104 N/C [outward]
C.
1.3 x 106 N/C [outward]
19. Two 2.0-kg spheres each carry a charge of 2.0 C. How does FE compare with Fg?
a. FE=Fg
b. Fg > FE
C.
d.
e.
FE>Fg
If the charges on the spheres are the same, then Fg > Få, but if the charges are opposite
then FE>Fg.
FE and Fg cannot be compared without knowing the distance between the spheres..

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