17-55. A uniform plate has a weight of 50 lb. Link AB is subjected to a couple moment of M = 10 lb ft and has a clockwise angular velocity of 2 rad/s at the instant 0 = 30°. Determine the force developed in link CD and the tangential component of the acceleration of the plate's mass center at this instant. Neglect the mass of links AB and CD. C 1.5 ft D = 30° A M 10 lb·ft = B 1 ft 2 ft

6/61 The body consists of a uniform slender bar and a uniform disk, each of mass m/2. It rests on a smooth surface. Determine the angular acceleration a and the acceleration of the mass center of the body when the force P = 6 N is applied as shown. The value of the mass m of the entire body is 1.2 kg. ✓ Answer a = 48.8 rad/s² CW from above āx = 0, āy = 5 m/s² P = 6 N m/2 -500 mm m/2 PROBLEM 6/61 200 mm

The assembly consisting of a uniform slender bar (mass = 1.5 kg and L = 0.49 m) and a rigidly attached uniform disk (mass = 6.8 kg) is freely pinned to point O on the collar that in turn slides on the fixed horizontal guide. The assembly is at rest when the collar is given a sudden acceleration a = 3.4 m/s² to the left as shown. Determine the initial angular acceleration a of the assembly. The angular acceleration is positive if counterclockwise, negative if clockwise. 6.8 kg Answer: a = i 1.5 kg LA rad/s²

The circular concrete culvert rolls with an angular velocity of w = 0.60 rad/s when the man is at the position shown. At this instant the center of gravity of the culvert and the man is located at point G, and the radius of gyration about G is kg = 3.7 ft (Figure 1) Figure 4 ft O 0.5 ft Part A Determine the angular acceleration of the culvert. The combined weight of the culvert and the man is 500 lb Assume that the culvert rolls without slipping, and the man does not move within the culvert. Express your answer to three significant figures and include the appropriate units. α = Submit μÀ Value Provide Feedback X Incorrect; Try Again Units Previous Answers Request Answer ? Units input for part A Next >

ANSWER= 3.621790, -9.99745 19 (aB)₂ = (aB)y 0 -12.49 A Two identical uniform slender rods with length 2.2 m and mass 3 kg are pin-connected at A. One of the rods is also pin-connected at its other end to fixed point O. If the system is released from rest in the position shown in the figure, find the initial acceleration of point Bat the end of the rightmost rod. The angle is 21°. For the purposes of reporting the acceleration, consider + to the right and +y upward. 3.8999 B x0% → x 0% m/s² m/s²

Slider 4 is moving downward at a speed of 14 = 2 m/s and with a downward acceleration of a = 0,25 m/s at the moment 0=60°. The slider is connected to a wheel of with a radius of R = 1.5 m with a rod of length L = 3 m. The wheel is rolling without slipping. VA ал C B VA OB R A) Sketch a diagram of the rod showing the location of its Instant Center at the moment shown. What is the distance, r from the instant center to to point A? A/IC' B) Using the rod's instant center, determine the angular speed of rod AB. C) Using a relative acceleration approach, determine the acceleration of point B.

Q1: The uniform slender bar of mass m and length L is released from rest when in the horizontal position shown. Determine its angular velocity and mass center speed as it passes the vertical position. Ans.: 3 @= 24g √7L CW, UG = 148L m 3L 4 14

The uniform 1,157-mm link AB slides up on frictionless rollers as shown below. At the instant shown, the link AB is vertical and the absolute velocity of point A is 19.9 m/s in the direction shown. Ignore the link thickness and roller diametres. For this configuration, 01=39 degrees and O2=25 degrees as shown. VA 01 A G Calculate the absolute velocity of the centre of mass at G. Give your answer in the form Z = 2 VGx + VGy in m/s where vGx is the horizontal component of the velocity vector (positive to the right) and VGy is the vertical component of the velocity vector (positive upwards). Round your final answer to two decimal places.

The 153-kg wheel has a radius of gyration about its center of mass O of kO = 283 mm. If it rotates counterclockwise at an angular speed of 1431 rev/min and the tension force applied to the braking band at A is TA = 1771N,a) Determine the angular acceleration, in rad/s2, so that the wheel comes to rest in 67.6 revolutions after TA and TB are applied.

The disk with radius r is rolling (without slipping) with angular velocity through the bottom of the circular path of radius R. If @= 2 rad/sec, R = 0.5 m, r = 0.2 m, and the mass of the disk is 3 kg, calculate the magnitude of the normal force exerted by the path on the disk at that instant. Present your answer in Newtons using 3 significant figures. ໙