12. Ammonia is a principal nitrogen fertilizer. It isprepared by the reaction between hydrogenand nitrogen.3H,(g) + N2(g)---->2NH3(g)In a particular reaction, 6.0 moles of NH3were produced. How many moles of H, andhow many moles of N, were reacted toproduce this amount of NH3 .

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12. Ammonia is a principal nitrogen fertilizer. It is prepared by the reaction between hydrogen and nitrogen. 3H,(g) + N2(g)---->2NH;(g) In a particular reaction, 6.0 moles of NH3 were produced. How many moles of H, and how many moles of N, were reacted to produce this amount of NH3.

12. Ammonia is a principal nitrogen fertilizer. It is prepared by the reaction between hydrogen and nitrogen. 3H,(g) + N2(g)---->2NH;(g) In a particular reaction, 6.0 moles of NH3 were produced. How many moles of H, and how many moles of N, were reacted to produce this amount of NH3.

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter5: Stoichiometry

Section: Chapter Questions

Problem 9RQ: Consider the following mixture of SO2(g) and O2(g). If SO2(g) and O2(g) react to form SO3(g), draw a...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

12. Ammonia is a principal nitrogen fertilizer. It is
prepared by the reaction between hydrogen
and nitrogen.
3H,(g) + N2(g)---->2NH3(g)
In a particular reaction, 6.0 moles of NH3
were produced. How many moles of H, and
how many moles of N, were reacted to
produce this amount of NH3 .

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