10 Calculate the pH at the equivalence point when 0.104 g sodium acetate (MM-82.0,Kb-5.6x10-¹0) Is dissolved in water to make 25.0 mL of solution and titrated with 0.0996M HCL (aq) a 10 A solution is 0.10M in FeCl₂. What is the pH necessary to just prevent the formation of iron (II) sulfide when the solution is saturated with H₂S ? Ka1, H₂S= 1.00 x107,Ka2, HS- = 1.3 x10-¹3; Ksp FeS=4.9x10-18

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Chapter17: Solubility And Complex-ion Equilibria
Section: Chapter Questions
Problem 17.130QP
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Show work for 10a and 10b. Please type in a clear and concise way Need asap. Thank you!
a
Calculate the pH at the equivalence point when 0.104 g sodium acetate (MM-82.0,Kb-5.6x10-10)
Is dissolved in water to make 25.0 mL of solution and titrated with 0.0996M HCL (aq)
10A
A solution is 0.10M in FeCl₂. What is the pH necessary to just prevent the formation of iron (II)
sulfide when the solution is saturated with H₂S? Ka1, H₂S= 1.00 x107,Ka2, HS-= 1.3 x10-13; Ksp
FeS=4.9x10-¹8
Transcribed Image Text:a Calculate the pH at the equivalence point when 0.104 g sodium acetate (MM-82.0,Kb-5.6x10-10) Is dissolved in water to make 25.0 mL of solution and titrated with 0.0996M HCL (aq) 10A A solution is 0.10M in FeCl₂. What is the pH necessary to just prevent the formation of iron (II) sulfide when the solution is saturated with H₂S? Ka1, H₂S= 1.00 x107,Ka2, HS-= 1.3 x10-13; Ksp FeS=4.9x10-¹8
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