1. What will be the phenotype of the fly that grows from the fertilized cell shown below? Allele key Dominant Recessive C- Curly wing B- Brown body L-Legs on head R- Red eyes C- normal wing b- black body |- antenna r- orange eyes O A. Normal wings, black body, antenna, and red eyes. • B. Curly wings, brown body, legs on head, and red eyes. OC. Curly wings, brown body, legs on head, and orange eyes. D. Normal wings, brown body, legs on head, and red eyes.

1. What will be the phenotype of the fly that grows from the fertilized cell shown below? Allele key Dominant Recessive C- Curly wing B- Brown body L-Legs on head R- Red eyes C- normal wing b- black body |- antenna r- orange eyes O A. Normal wings, black body, antenna, and red eyes. • B. Curly wings, brown body, legs on head, and red eyes. OC. Curly wings, brown body, legs on head, and orange eyes. D. Normal wings, brown body, legs on head, and red eyes.

Biology: The Unity and Diversity of Life (MindTap Course List)

15th Edition

ISBN:9781337408332

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter13: Observing Patterns In Inherited Traits

Section: Chapter Questions

Problem 8GP: In sweet pea plants, an allele for purple flowers. (P) is dominanl when paired with a recessive...

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Name: 2. Some ladybugs have 10 black spots on their shells and some have 4. When true breeding 10 spot individuals are crossed with true breeding 4 spot individuals, the offspring have 7 spots. a. Propose two distinct explanations for this finding. Explain the nature of spot inheritance in each case. D. rew bacteria erred them figure above would of14N7 then ely 2 moldon omrod abitqaq ratlsmmem sge of delw toiisoibom s s neu not oomod aid to soubnup ogusl onomod odi to slevel ismon oouborg o o consu ud od souboini bluow uoy dairlw yd za00oq sdi mialex b. Propose an experiment that would distinguish between these possibilities. sor proieins
III. Dihybrid crosses Two loci with two autosomal recessive traits Gene symbols a apterous wing size A normal wing size s sepia eye color S red eye color Be careful, S and s look alike when hand written The parents were apterous, red eyed color female and normal wing size, sepia eyed coloredmale (figure out the genotypes) Diagram of P1 cross: You are crossing AaSs with AaSs. Diagram of F1 cross: Give expected F2 phenotypic ratio: Give expected F2 genotypic ratio: IV. Other dihybrid cross Gene symbols v vestigial wing size V normal wing size s sepia eye color S red eye color The parents were vestigial, red eyed color female and normal wing size, sepia eyed color male…
15. B. You set up a cross between a male fruit fly with lobe eyes and a true breeding female fruit fly with reduced bristles and disrupted wings. In the F1 offspring you see the all the flies have WT bristles and WT wings. However, half the flies have WT eyes and half the flies have lobe eyes. You take 20 of the F1 female flies with lobe eyes and mate them to 20 true breeding male flies with reduced bristles and disrupted wings and observe the following offspring: 164 lobe eyes and reduced bristles 137 lobe eyes and disrupted wings 638 reduced bristles and disrupted wings 152 reduced bristles 40 wildtype 175 disrupted wings 659 lobe eyes 35 lobe eyes reduced bristles and disrupted wings Calculate the interference for this region.
2. Cross a homozygous two horned zork with a heterozygous two horned.zork. A. What are the genotypes of the possible offspring? H Gendrere ны 3. Cross alheterozygous green haired zork with a heterozygous green haired zork. A. What are the genotypes and phenotypes of the possible offspring? ✓homozygous 4. Cross a green lipped zork with a heterozygous purple lipped zork.) A. What are the number of phenotypes and genotypes of the offspring? Hint: Count what is in the boxes! 5. Tork, who is homozygous for tall meets Vorkina, who is short. A. What are the phenotypes and genotypes if they were to have offspring?
7. Here are the results of a crossing trial with fruit flies (D. melanogaster) Parents: Ebony bodied, white-eyed 9 fly x Normal-bodied, red-eyed a fly • Both parents were from true-breeding (homozygous) lines • Ebony body means the body colour is black instead of orange F1: Males All white-eyed, normal bodied Females Red eyed, normal bodied F2: (200 offspring in total produced) Male Females Normal body, red eye Normal body, white eye Ebony body, red eye Ebony body, white eye Total 38 36 37 39 12 11 13 14 100 100 Explain the pattern of inheritance of each trait body colour and eye colour Write the genotype of the parents, F1 offspring and F2 offspring. (ii)
5. The ability to taste PTC paper is controlled by a dominant gene. The ability to taste (T) PTC is 1ueunuop sno8Ázounu ae RIR dominant over the inability to taste (t) PTC. Normal skin (N) is dominant over albino skin (n). Two tasters, normally pigmented, have an albino son and a non-taster daughter. Show the cross between the parents. Genotype of mom Genotype of dad Genotypes Phenotypes What is the chance that the albino son is a taster? What is the chance that the non-taster daughter is an albino? What is the chance that the non-taster daughter is a carrier of the albino trait? What is the chance of getting offspring who are heterozygous for both traits?
3. Describe the genotype of cats with the following phenotypes (Describe only the genes that are not homozygous for the wild type): A grey cat with small white patches. oo/oY W_ [Choose ] dd Ss TA_ A white cat with orange spots. oo dd mcmc oo/oY W_ ctct bb TA_ A pale colored cat with brown tips to its tail, ears, paws, and snout. ctct bb TA_ oo dd mcmc A cream-colored cat with darker cream color forming broad bands and whorls along its body.
4. Albinism is caused bya recessive al lele. A brown rabbit crossed with an albino rabbit produces 12 brown offspring. When the albino rabbit is crossed with a second brown rabbit, 7 brown and 5 albino offspring are produced. What is the best explanation for this genetic situation? Write the genotypes of each of the parents and their offspring. A First set of parents First set of offspring Cenng to ri Second set of parents e 1:s!! A A Second set of offspring Sbl
5. Flower color is determined by the pathway below. You a crossing a true-breeding white-flowered plant thatcannot produce gene A and a true-breeding white-flowered plant that cannot produce gene B.Gene A Gene BWhite  White  Purplea. What are the genotypes of the P-generation?b. What are the genotypes and phenotypes of the F1 generation?c. What are the genotypes and phenotypes of the F2 generation? What is the phenotypic ratio?(Purple:White)
In sweet pea plants, an allele for purple flowers. (P) is dominanl when paired with a recessive allele for red flowers (p). An allele for Jang pollen grains (L) is dominant when paired with a recessive allele for round pollen grains (L). Bateson and Punnett crossed a plant having purple flowers and long pollen grains with one having white flowers and round pollen grains. All F1 offspring have purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple /lower/ round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?
Several alleles affect traits of roses, such as plant form and bud shape. Alleles of one gene govern whether a plant will be a climber (dominant) or shrubby (recessive). All F1 offspring from a cross between a true-breeding climber and a shrubby plant are climbers. If an F1 plant is crossed with a shrubby plant, about 50 percent of the offspring will be shrubby; 50 percent will be climbers. Using symbols A and a for the dominant and recessive alleles, make a Punnett- square diagram of the expected genotypes and phenotypes the cross between the F1 offspring and the shrubby plant.
Choose the statement that is incorrect. a. A son can inherit a recessive allele on an X chromosome from either parent. b. An individual may inherit three or more of each type of chromosome characteristic or the species, a condition called polyploidy. c. A female child inherits one X chromosome from her mother and one from her father. d. Pedigree analysis can be used to determine a future childs chance of being born with achcondroplasia.