1. 2. 3. a. b. Solve: y' + x² a. b. (1+y²) (x-1) x²+2x+2 In |x-1| +2 Arc tan y = C x-2x-2 In (x + 1|-2 Arc tan y = C x²+2x+2 In |x-1| +2 Arc cot y = C d. x²+2x+2 ln x + 11 +2 Arc cot y = C C. Solve: y' + sec x tan y = 0 In |csc x-cot x cos y = C In scc x-tan xl cos y = C In [sec x+tan x| sin y = C d. In csc x + cot x) sin y = C C. Solve: y'= X(1+y) y (1-x) a. C+x-y=In(1+y) =0 (1-x) b. C-x-y-In (1+y) (1-x) C. C+x+y= ln (1+y) (1-x) d. C-x+y=ln (1+y) (1-x)

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
Problem 20CR
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PLEASE ANSWER ALL OF THIS QUESTION ASAP!!! " DIFFERENTIAL EQUATION"

1.
2.
3.
= 0
x²+2x+2 In |x-1| +2 Arc tan y=C
x-2x-2 In (x + 1|-2 Arc tan y = C
x²+2x+2 In |x-1| +2 Arc cot y = C
x²+2x+2 ln x +11+2 Arc cot y = C
Solve: y' + x²(1+y)
(x-1)
a.
b.
d.
Solve: y' + sec x tan y = 0
a.
a.
b.
c.
In [sec x + tan x sin y = C
d. In jcsc x + cot x) sin y = C
In csc x-cot x cos y = C
In sec x-tan xl cos y = C
Solve: y'= x(1+y)
y (1-x)
C+x-y=In(1+y)
(1-x)
C-x-y-In (1+y)
(1-x)
b.
C. C+x+y= In (1+y)
(1-x)
d. C-x+y= ln (1+y)
(1-x)
Transcribed Image Text:1. 2. 3. = 0 x²+2x+2 In |x-1| +2 Arc tan y=C x-2x-2 In (x + 1|-2 Arc tan y = C x²+2x+2 In |x-1| +2 Arc cot y = C x²+2x+2 ln x +11+2 Arc cot y = C Solve: y' + x²(1+y) (x-1) a. b. d. Solve: y' + sec x tan y = 0 a. a. b. c. In [sec x + tan x sin y = C d. In jcsc x + cot x) sin y = C In csc x-cot x cos y = C In sec x-tan xl cos y = C Solve: y'= x(1+y) y (1-x) C+x-y=In(1+y) (1-x) C-x-y-In (1+y) (1-x) b. C. C+x+y= In (1+y) (1-x) d. C-x+y= ln (1+y) (1-x)
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