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1 σου. 150 Ω ΑΛΛ www 200 ΩΣ 100 Ω Figure 1 1 601-

1 σου. 150 Ω ΑΛΛ www 200 ΩΣ 100 Ω Figure 1 1 601-

Inquiry into Physics
Inquiry into Physics
8th Edition
ISBN:9781337515863
Author:Ostdiek
Publisher:Ostdiek
Chapter7: Electricity
Section: Chapter Questions
Problem 34Q
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Reclung.c A on ri gle Figure 1 2. The circuit shown above is constructed with two 6.0 V batteries and three resistors with the values shown. The currents 1₁, 12, and 13 in each branch of the circuit are indicated. 2 GEOMETRY AND TRIGONOMETRY Circle A = ²² C = 2πr Cy.inder bh - re Rectangular Solid Vlh Sphere 1. Using Kirchhoff's rules, write, but DO NOT SOLVE, equations that can be used to solve for the current in each resistor. ii. Calculate the current in the 200 9 resistor. iii. Calculate the power dissipated by the 200 2 resistor. V = ar²l S.. Figure 2 The two 6.0 V batteries are replaced with a battery with voltage & and a resistor of resistance 50 2, as shown above. The voltmeter V shows that the voltage across the 200 £2 resistor is 4.4 V. (b) Calculate the current through the 50 2 resistor. (c) Calculate the voltage & of the battery. V=² S = 4; 7² Rig Triangle 2 +6² = c² sin = COS== tan 8 = OJA b C 2m. a b 6.0 V 7,4 & A - area C=circumference h-hei £= le L W = IUL r=fuu.0 V-volume S=sur. ce arca 1. FC 5 arc le t ung.e 50 150 Ω www 1₂ 200 ΩΣ ADVANCED PLACEMENT PHYSICS C EQUATIONS b 150 92 www 100 £2 www 90% Ta 6.0 V 100 92 a 200 ΩΣ (V) 50 ΩΣ CALCULUS df df du du dx (*²)= (e) = ae (In cx) == [sin(x)] = acos(x) cs(x)] = x √x²dx=¹¹_n-1 Joth dx = 10 mx-1 dx √ = In|x + al [cos(ax)dx = =sin(x) [sin (ax) dx = cos(x) VECTOR PRODUCTS A-B= AB cose |Ã x B= ABsine
Transcribed Image Text:Reclung.c A on ri gle Figure 1 2. The circuit shown above is constructed with two 6.0 V batteries and three resistors with the values shown. The currents 1₁, 12, and 13 in each branch of the circuit are indicated. 2 GEOMETRY AND TRIGONOMETRY Circle A = ²² C = 2πr Cy.inder bh - re Rectangular Solid Vlh Sphere 1. Using Kirchhoff's rules, write, but DO NOT SOLVE, equations that can be used to solve for the current in each resistor. ii. Calculate the current in the 200 9 resistor. iii. Calculate the power dissipated by the 200 2 resistor. V = ar²l S.. Figure 2 The two 6.0 V batteries are replaced with a battery with voltage & and a resistor of resistance 50 2, as shown above. The voltmeter V shows that the voltage across the 200 £2 resistor is 4.4 V. (b) Calculate the current through the 50 2 resistor. (c) Calculate the voltage & of the battery. V=² S = 4; 7² Rig Triangle 2 +6² = c² sin = COS== tan 8 = OJA b C 2m. a b 6.0 V 7,4 & A - area C=circumference h-hei £= le L W = IUL r=fuu.0 V-volume S=sur. ce arca 1. FC 5 arc le t ung.e 50 150 Ω www 1₂ 200 ΩΣ ADVANCED PLACEMENT PHYSICS C EQUATIONS b 150 92 www 100 £2 www 90% Ta 6.0 V 100 92 a 200 ΩΣ (V) 50 ΩΣ CALCULUS df df du du dx (*²)= (e) = ae (In cx) == [sin(x)] = acos(x) cs(x)] = x √x²dx=¹¹_n-1 Joth dx = 10 mx-1 dx √ = In|x + al [cos(ax)dx = =sin(x) [sin (ax) dx = cos(x) VECTOR PRODUCTS A-B= AB cose |Ã x B= ABsine
v=x0+ axt x = xo + x² + ₂a 2=²+2a₂ (-0) F ΣF F - m m |J = √F 1 = Ap p = mv FSHF AE=W=F-dr P = dt P = F.j AU = mg h 4 = 2²2 = 6³²7 T =FxP à-4-44 1-Sr dm = 2mr¹ Σm.x, m₂ Xcm- V=Y@ = F x1 = lo K= @=000 + at 6 = 6 + + ½a²² UNIT SYMBOLS ₁-2 B MECHANICS Factor Prefix 10⁹ giga 10 10³ PREFIXES mega kilo centi milli micro 16 1.9 nano 10-12 pico J a E- ene y = _orce F= С ADVANCED PLACEMENT PHYSICS C EQUATIONS It I 1 m n P 7 Jm, ulse --.cy enc = .ght - kinetic e e y k spring constant l = len ul acceleration Langu. ar...mentu.... 7h = mass P = 0::cr p mo...ent m Symbol G M k otatio ali e tia = 1 = ....e a 5 . ampere, kelvin, T Jotential ener ty OCH evioa = elocity or s, cea W = work done on a > stem X Proton mass, m, 1.67 x 10 27 kg Net ron... ss, m, = 1.67 x 10 kg Electron mass, m, = 9.11 10-31 kg A og du's numbe, N = 5.02 x 1023 mol-1 Universal gas constant, R = 8.31 J/(mol-K) Boltzmann's constant, kg = 1.38 x 10-23 J/K 1 unified atomic mass unit, Planck's constant, e-angle osition = coefficient of friction d.sta ce R = -KAX torque a gulur speed a guluf acceleration plase a gle m meter, kilogram, kg second, S A K U. - * (4x)² J = max cos(col + 0) 1-²-3-7 = T₁ = 2₁ 1₂ =2= √// |Fal - Gimm Ug = Gm,m₂ r ||FR|- 1992 Aneo F₂ mole, mol hertz, Hz. newton, N pascal, Pa joule, J oine cose tane $8-dÀ=& E-di- dV X AV = -√E-dir E₁ =- ELECTRICITY AND MAGNETISM A = area - B magnetic field C = capacitance distance E electric field emf E -force V = 159 Arzo C- U₂ -97= AV = 2 C=EC G-24 1-d = R-PL = لم = F 1 = Nev A ΔΙΑ R.-ER ΣΕ ADVANCED PLACEMENT PHYSICS C TABLE OF INFORMATION NLANIS AND CONVERN FIORS Ε-ΣΕ R P P = 1AV 1 9192 Απερ T Electron charge na gn..ude, Uc-AV=C(AV)² = He Idex 4 Sd of light, Universal gravitational constant, Acceleratio i due to gravity at Earth su..ace, 1 = current J= current density - L-inductance <= length n = number of loops of wire per unit length N number of charge carriers per unit volume PR watt, coulomb, volt, ohm, henry, P = power Q-charge Vac ium permittiv t,, Coulomb's law constant, k = 1/(4n) = 9.0x10° (Nm²)/c² Vacuum permeability. Ho = 4 x 10 (T-m)/A Magnetic constant, k = Ho/(4x) = 1x 10-7 (T-m)/A 1 atmosphere ressure, R- resistance r = radius or distance t-time W C V Ω H = point c' arge J= potential or stored energy ✓= electric potential v = velocity or speed p = resistivity - flux x = dielectric constant Fy=qvxB b-dl=Hol .7 0 1/2 3/5 √2/2 1 0 √3/2 4/5 √3/3 3/4 F-S1 dixB B₂ = onl •=fBui 8 150x1¹9 e cron ol, 1 V-1.60 x 10 'J c = ..00 x 10 m/s G=7 x 10-¹1 (N-m²j/kg² 8 = 9.8 m/s² =$E-di- dl 8 = -1 U₁--1-4² 1 u = 1.66 x 10-27 kg = 931 MeV/e² h = 6.63 x 10-34 J-s = 4.14 x 10-15 eV-s h: 1.99 x 10-25 J-m = 1.24 x 10³ eV nm 8 = 8.85 x 10-¹2 c²/(N-m²) 1 atm = 1.0 x 10' N/m² = 1.0 x 10³ Pa farad, tesla. degree Celsius, electron volt, 60° 4/5 √3/2 3/5 √2/2 1 4/3 W VALUES OF TRIGONOMETRIC FUNCTIONS FOR COMMON ANGLES 0. 0° 30° 90° 1 0 1/2 √√ dt F T C eV 80 The following assumptions are used in this exam. I. The frame of reference of any problem is inertial unless otherwise stated. II. The direction of current is the direction in which positive charges would drift. V. Edge effects for the electric field of a parallel plate capacitor are negligible unless otherwise stated. III. The electric potential is zero at an infinite distance from an isolated point charge. IV. All batteries and meters are ideal unless otherwise stated.
Transcribed Image Text:v=x0+ axt x = xo + x² + ₂a 2=²+2a₂ (-0) F ΣF F - m m |J = √F 1 = Ap p = mv FSHF AE=W=F-dr P = dt P = F.j AU = mg h 4 = 2²2 = 6³²7 T =FxP à-4-44 1-Sr dm = 2mr¹ Σm.x, m₂ Xcm- V=Y@ = F x1 = lo K= @=000 + at 6 = 6 + + ½a²² UNIT SYMBOLS ₁-2 B MECHANICS Factor Prefix 10⁹ giga 10 10³ PREFIXES mega kilo centi milli micro 16 1.9 nano 10-12 pico J a E- ene y = _orce F= С ADVANCED PLACEMENT PHYSICS C EQUATIONS It I 1 m n P 7 Jm, ulse --.cy enc = .ght - kinetic e e y k spring constant l = len ul acceleration Langu. ar...mentu.... 7h = mass P = 0::cr p mo...ent m Symbol G M k otatio ali e tia = 1 = ....e a 5 . ampere, kelvin, T Jotential ener ty OCH evioa = elocity or s, cea W = work done on a > stem X Proton mass, m, 1.67 x 10 27 kg Net ron... ss, m, = 1.67 x 10 kg Electron mass, m, = 9.11 10-31 kg A og du's numbe, N = 5.02 x 1023 mol-1 Universal gas constant, R = 8.31 J/(mol-K) Boltzmann's constant, kg = 1.38 x 10-23 J/K 1 unified atomic mass unit, Planck's constant, e-angle osition = coefficient of friction d.sta ce R = -KAX torque a gulur speed a guluf acceleration plase a gle m meter, kilogram, kg second, S A K U. - * (4x)² J = max cos(col + 0) 1-²-3-7 = T₁ = 2₁ 1₂ =2= √// |Fal - Gimm Ug = Gm,m₂ r ||FR|- 1992 Aneo F₂ mole, mol hertz, Hz. newton, N pascal, Pa joule, J oine cose tane $8-dÀ=& E-di- dV X AV = -√E-dir E₁ =- ELECTRICITY AND MAGNETISM A = area - B magnetic field C = capacitance distance E electric field emf E -force V = 159 Arzo C- U₂ -97= AV = 2 C=EC G-24 1-d = R-PL = لم = F 1 = Nev A ΔΙΑ R.-ER ΣΕ ADVANCED PLACEMENT PHYSICS C TABLE OF INFORMATION NLANIS AND CONVERN FIORS Ε-ΣΕ R P P = 1AV 1 9192 Απερ T Electron charge na gn..ude, Uc-AV=C(AV)² = He Idex 4 Sd of light, Universal gravitational constant, Acceleratio i due to gravity at Earth su..ace, 1 = current J= current density - L-inductance <= length n = number of loops of wire per unit length N number of charge carriers per unit volume PR watt, coulomb, volt, ohm, henry, P = power Q-charge Vac ium permittiv t,, Coulomb's law constant, k = 1/(4n) = 9.0x10° (Nm²)/c² Vacuum permeability. Ho = 4 x 10 (T-m)/A Magnetic constant, k = Ho/(4x) = 1x 10-7 (T-m)/A 1 atmosphere ressure, R- resistance r = radius or distance t-time W C V Ω H = point c' arge J= potential or stored energy ✓= electric potential v = velocity or speed p = resistivity - flux x = dielectric constant Fy=qvxB b-dl=Hol .7 0 1/2 3/5 √2/2 1 0 √3/2 4/5 √3/3 3/4 F-S1 dixB B₂ = onl •=fBui 8 150x1¹9 e cron ol, 1 V-1.60 x 10 'J c = ..00 x 10 m/s G=7 x 10-¹1 (N-m²j/kg² 8 = 9.8 m/s² =$E-di- dl 8 = -1 U₁--1-4² 1 u = 1.66 x 10-27 kg = 931 MeV/e² h = 6.63 x 10-34 J-s = 4.14 x 10-15 eV-s h: 1.99 x 10-25 J-m = 1.24 x 10³ eV nm 8 = 8.85 x 10-¹2 c²/(N-m²) 1 atm = 1.0 x 10' N/m² = 1.0 x 10³ Pa farad, tesla. degree Celsius, electron volt, 60° 4/5 √3/2 3/5 √2/2 1 4/3 W VALUES OF TRIGONOMETRIC FUNCTIONS FOR COMMON ANGLES 0. 0° 30° 90° 1 0 1/2 √√ dt F T C eV 80 The following assumptions are used in this exam. I. The frame of reference of any problem is inertial unless otherwise stated. II. The direction of current is the direction in which positive charges would drift. V. Edge effects for the electric field of a parallel plate capacitor are negligible unless otherwise stated. III. The electric potential is zero at an infinite distance from an isolated point charge. IV. All batteries and meters are ideal unless otherwise stated.
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