1 mol of nitroethane is allowed to expand isothermally at T = 400 K from 1 m³ to 5 m³. If nitroethane obeys the Soave-Redlich-Kwong (SRK) equation of state, calculate the values of q, w, AU, AH, and AS. The SRK EOS is given by:

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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1 mol of nitroethane is allowed to expand isothermally at T = 400 K from 1 m³
to 5 m³. If nitroethane obeys the Soave-Redlich-Kwong (SRK) equation of state, calculate
the values of q, w, AU, AH, and AS. The SRK EOS is given by:
RT
a(Т)
P =
V -b (V+ eb)(V+ob)
a(T)
V -b
RT
V = 1 +b –
P
P (V+ eb)(V + ob)
a(T,)R°T?
a(T) = y
Pe
RT.
b = 2.
P.
Eq. of state
a(T,)
Ω
RK (1949)
SRK (1972)
PR (1976)
T,-V2
CSRK(T,; 0)'
CpR(T,; 0)'
1
1
1+ V2 1- V2
0.08664
0.08664
0.42748
0.42748
0.45724
0.07780
*Smith, Van Ness, and Abbott, Introduction to Chemical Engineering Ther-
modynamics, 7th ed., p. 98, McGraw-Hill, New York (2005).
'OSRK(T,; 0) = [1 + (0.480 + 1.574 – 0.176²) (1 - T,V2)]²
'aPR(T,; 0) = [1 + (0.37464 + 1.542260 – 0.269920²) (1 – T,V2)]²
where Pe, Ve, and Te are the critical constants and o is the acentric factor, all of which can
be obtained from Perry's Chemical Engineering Handbook 8th Edition.
Transcribed Image Text:1 mol of nitroethane is allowed to expand isothermally at T = 400 K from 1 m³ to 5 m³. If nitroethane obeys the Soave-Redlich-Kwong (SRK) equation of state, calculate the values of q, w, AU, AH, and AS. The SRK EOS is given by: RT a(Т) P = V -b (V+ eb)(V+ob) a(T) V -b RT V = 1 +b – P P (V+ eb)(V + ob) a(T,)R°T? a(T) = y Pe RT. b = 2. P. Eq. of state a(T,) Ω RK (1949) SRK (1972) PR (1976) T,-V2 CSRK(T,; 0)' CpR(T,; 0)' 1 1 1+ V2 1- V2 0.08664 0.08664 0.42748 0.42748 0.45724 0.07780 *Smith, Van Ness, and Abbott, Introduction to Chemical Engineering Ther- modynamics, 7th ed., p. 98, McGraw-Hill, New York (2005). 'OSRK(T,; 0) = [1 + (0.480 + 1.574 – 0.176²) (1 - T,V2)]² 'aPR(T,; 0) = [1 + (0.37464 + 1.542260 – 0.269920²) (1 – T,V2)]² where Pe, Ve, and Te are the critical constants and o is the acentric factor, all of which can be obtained from Perry's Chemical Engineering Handbook 8th Edition.
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