1) Given that volume change of mixing A and B is AVM = 8.4XXB (cc/mol)— a. Calculate and tabulate, AVM for mole fractions of XA ranging from 0 to 1. b. Plot AVM VS XA C. Calculate the equations for AVM and ſѾ. d. Calculate, tabulate, and plot AVM and AVM for mole fractions of XA ranging from 0 to 1. B e. Show that calculated AVM and AVM are correct by calculating AVM from them.
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- 1. Part A Solution temperature = 24 °C Conductivity of instrument grade water = 1.043 uScm! Conductivity of deionised water = 1.74 µScm! Conductivity of tap water = 330 μScml On the basis of data above comment on conditions of the different water grades. 2. The experimental data for electrolytes in Part B are given below: Electrolyte c (M) K (ms.cm') HC1 0.01 5.06 KCI 0.01 1.415 NaCl 0.01 1.236 CaCl2 0.01 2.30 КОН 0.01 2.29 CH3OH 0.01 0.003 K2SO4 0.01 2.65 Calculate molar conductivity A of each electrolyte solution in Sm/mol above. Correct for the conductivity of deionized water.3. Find the molar fraction of HCI in vapors over solution of 1.86 g of HCI in 100 g of benzene. Total pressure over that solution equals at 293 K equals to 101 325 Pa. Henry's constant for HCI under this conditions equals to 4.195-10“ kPa". Mc = 12.01 g-mol", M = 1.01 g-molr, Ma= 35.45 g-mol.What is meant by a "negative deviation from Raoult's Law" for a mixture of two volatile compounds, and what causes such a deviation to occur? Format BIU 三 三= ... Format
- 44). Calculate the solubility of Pbl2 in moles/L in pure water at 25 °C. The Ksp for Pbl2 is 9.80 x 10-9 at 25 °C. Use 3 Sif. Fig. in the answer. а. 9.80 х 10-9 М d. 4.95 x 10-5 М b. 0.00135 M e. none of the above с. 9.80 х 105 МA 18 g of unknown organic sample was dissolve in 756 mL of benzene. The boiling point of benzene was increased by 3.36oC. As the first step of analysis, determine the moecular weight of the unknow sample? Kb of benzene= 2.64oC/m Bb of benzene = 80.09 oC density of benzene = 0.874 g/mL at 25 °C Answer in whole number, no units required.2. A on is made by mixing 1.08 g of an unknown non-volatile non-electrolyte with g of benzene. The free 10.00 zing point of pure benzene is 5.5°C. The molal reezin ng point depression constant, K for benzene is 5.12°C/molal. The following data were obtained in a freezing point depression experiment Time, min Temperature C TemperatureC 0.5 0.1 0.8 0.9 0.8 0.7 0.6 0.5 0.4 0.2 -0.5 1.2 Time min 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0 23.8 22.1 20.2 18.5 16.6 14.8 12.7 10.8 9.1 7.2 5.5 3.6 13.0 14.0 15.0 16.0 17.0 18.0 19.0 20.0 21.0 22.0 23.0 24.0 25.0 Plot a graph of time/temperature, using the y-axis for temperature and the x-axis for time. Determine the freezing point of the solution. A. 2 De-tereine tHe alality of the solthon
- If 30.0 mL of water that is 0.0500 M in Q is to be extracted with four 10.0-mL portions of an immiscible organic solvent, what is the minimum distribution coefficient that allows transfer of all but the following percentages of the solute to the organic layer: (a) 1.00 X10-24 (b) 1.00 X10-22Assuming 100% dissociation, calculate the freezing point (T) and boiling point (T) of 2.05 m Na₂SO4 (aq). Colligative constants can be found in the chempendix. f Tf= Tь = psy HW 3.pdf APA Title Page....doc D PSY Final Project....pdf 'C15. Explain why inorganic compounds such as MgCO, which are unsta- ble when exposed to heat, can induce an error n the measurement of volatile solids. 16. Use an anion-cation balance to determine if the following sample analysis for waters 1 and 3 is acceptable.
- BC Broward Col x O Onelogin xe Expt. 6 pre-l xA "Expt. 7 Quiz X G .What is an x b ziprecruiter x O 12.628+ Par X E Login x + O File | C/Users/nerbs/Downloads/Expt.%207%20Quiz,%20Part%201.pdf 10 2) If absorptivity (the constant of how much light of a given wavelength the sample absorbs) and path length (how much solution there is for light to pass through) are the same, which is true for a Beer's Law solution? a) its concentration and absorbance are proportional b) its concentration and rate are proportional c) its absorbance and rate are proportional d) the solution is an alcoholic beverageExam card VARIANT 4 1. A solution was obtained by dissolving 25 grams of nonelectrolyte in 1000 grams of water. The freezing temperature for this solution equals as to-1.55 °C. Determine the molar mass of dissolved substance. Cryoscopic constant for water equals to 1.86 K.Kg/mol.PDF chem_353_2020-2021_final.pdf Dosya | C:/Users/Asus/Downloads/chem_353_2020-2021_final.pdf Solubility of KNO3 70 Answer the following 3 questions by using this sohubility graph of KNO3. O 60 50 O 40 30 20 10 10 20 30 40 50 60 70 80 90 Temperature (c) a) What happens to a solution of KNO3 that is saturated at 50°C when it is cooled quickly to 10°C? EXPLAIN. b) How would you describe a solution of KNO3 at 80°C if there are about 45 g of KNO3 dissolved in 100 g of water? EXPLAIN. c) How many grams of KNO3 need to be dissolved in 300 g of water in order to have a saturated solution Solubility (g/100 g) of