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-1 Consider the curve given by the equation (a) Verify that point (2, 1) is on the curve. ³ + 7y=x³ y- -2 (b) Find the point on the curve that has the coordinate equal to The following is a graph of the equation using Mathematica. ContourPlot|y³ +7 y = x^3, {x, -5, 5}, {y, -3, 3), Epilog → {PointSize [Large], Blue, Point [ {2, 1}], Red, nt [{-√√22, -2}]}] Point 2

-1 Consider the curve given by the equation (a) Verify that point (2, 1) is on the curve. ³ + 7y=x³ y- -2 (b) Find the point on the curve that has the coordinate equal to The following is a graph of the equation using Mathematica. ContourPlot|y³ +7 y = x^3, {x, -5, 5}, {y, -3, 3), Epilog → {PointSize [Large], Blue, Point [ {2, 1}], Red, nt [{-√√22, -2}]}] Point 2

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 41E
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Practice 1: Consider the curve given by the equation (a) Verify that point (2, 1) is on the curve. y- -2 (b) Find the point on the curve that has the coordinate equal to The following is a graph of the equation using Mathematica. ContourPlot|y³ +7 y = x^3, {x, -5, 5}, {v, -3, 3), Epilog → {PointSize [Large], Blue, Point [ {2, 1}], Red, Point [{-√√22, -2}]}] -4 -2 y³ +7y=x³ 0 2 4
Transcribed Image Text:Practice 1: Consider the curve given by the equation (a) Verify that point (2, 1) is on the curve. y- -2 (b) Find the point on the curve that has the coordinate equal to The following is a graph of the equation using Mathematica. ContourPlot|y³ +7 y = x^3, {x, -5, 5}, {v, -3, 3), Epilog → {PointSize [Large], Blue, Point [ {2, 1}], Red, Point [{-√√22, -2}]}] -4 -2 y³ +7y=x³ 0 2 4
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