Biology
Biology
12th Edition
ISBN: 9780134813448
Author: Audesirk, Teresa, Gerald, Byers, Bruce E.
Publisher: Pearson,
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Chapter 14.4, Problem 1TC

For any single person, a given STR always has either one or two bands. Why? Further, single bands are always about twice as bright as each band of a pair. For example, in the D16 STR on the right, the single bands of the first and third DNA samples are twice as bright as the pairs of bands of the second, fourth, and fifth samples. Why?

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How would you estimate the size of the unknown DNA fragement just by looking at the gel?
DNA from 100 unrelated individuals from one population of Chinook salmon were amplified at a single microsatellite locus, and run on an agarose gel. The results from gel electrophoresis shows three different fragment lengths (i.e. alleles/band positions) corresponding to 3 alleles; Allele F (250bp), Allele R (180bp), and Allele Y (100bp). The numbers at the top of each lane is the number of fish observed with that particular genotype or banding pattern in the population. Note that a single band means a homozygote for that allele (band size). a) Calculate the allele frequency for Allele Y. (b) Calculate the genotype frequencies for the following genotypes: FF, FR, and RY. (c) What is the expected number of Chinook salmon with homozygous genotype for allele Y in the study population? (d)What is the name of the statistical test that you could conduct to test whether this population of Chinook salmon is in Hardy Weinberg Equilibrium
Below are 9 possible primer pairs.● Determine which primer pair is the best choice.● Explain why the other primers are not good choices.● Calculate the Tm for each primer. Underline or highlight the region of DNA for the primer pair you chose as the best.Forward 1: 5’ gaaataattttgtttaactttaag 3’ Tm =Reverse 1: 5’ gtttaagacaaaatagtctgg 3’ Tm =Forward 2: 5’ gtaactcagctttcaggtcg 3’ Tm =Reverse 2: 5’ tctcggaatgttgcaacagc 3’ Tm =Forward 3: 5’ agattagcggatcctacctg 3’ Tm =Reverse 3: 5’ atgtgtaatcccagcagcag 3’ Tm =Forward 4: 5’ cattgattatttgcacggcg 3’ Tm =Reverse 4: 5’ aaaatcttctctcatccgcc 3’ Tm =Forward 5: 5’ tccataagattagcggatcc 3’ Tm =Reverse 5: 5’ tgcaagcttggctgttttgg 3’ Tm =Forward 6: 5’ gatcctacctgacgcttttta 3’ Tm=Reverse 6: 5’ aaataatgaattcgagctcggt 3’ Tm =Forward 7: 5’ataaaaaaatcgagataaccgtt 3’ Tm =Reverse 7: 5’aggtcgactctagaggatc 3’ Tm =Forward 8: 5’ctacctgttccatggccaac 3’ Tm=Reverse 8: 5’ ttcgggcatggcactcttg 3’ Tm=Forward 9: 5’ tccataagattagcggatcc 3’ Tm =Reverse 9: 5’…

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