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You run a regression analysis on a bivariate set of data (n = 10). With the regression equation What is the predicted response value? y = = y = -1.328x +98.376 with a correlation coefficient of r = -0.119. You want to predict what value (on average) for the response variable will be obtained from a value of x = 50 as the explanatory variable. (Report answer accurate to one decimal place.) 29.5 and y = 59.2, you obtain

You run a regression analysis on a bivariate set of data (n = 10). With the regression equation What is the predicted response value? y = = y = -1.328x +98.376 with a correlation coefficient of r = -0.119. You want to predict what value (on average) for the response variable will be obtained from a value of x = 50 as the explanatory variable. (Report answer accurate to one decimal place.) 29.5 and y = 59.2, you obtain

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section: Chapter Questions
Problem 4SGR
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Question 15 > You run a regression analysis on a bivariate set of data (n = 10). With the regression equation What is the predicted response value? y = = y = -1.328x + 98.376 with a correlation coefficient of r = -0.119. You want to predict what value (on average) for the response variable will be obtained from a value of x = 50 as the explanatory variable. (Report answer accurate to one decimal place.) Question Help: Message instructor 29.5 and y = 59.2, you obtain
Transcribed Image Text:Question 15 > You run a regression analysis on a bivariate set of data (n = 10). With the regression equation What is the predicted response value? y = = y = -1.328x + 98.376 with a correlation coefficient of r = -0.119. You want to predict what value (on average) for the response variable will be obtained from a value of x = 50 as the explanatory variable. (Report answer accurate to one decimal place.) Question Help: Message instructor 29.5 and y = 59.2, you obtain
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