Using Kroning panney modal of P < 1. Prove that energy of lowest energy bank (k = 0) is h²p ma²

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Using Kroning panney modal of P < 1.
Prove that energy of lowest energy bank
(k = 0) is
h²p
ma²
Transcribed Image Text:Using Kroning panney modal of P < 1. Prove that energy of lowest energy bank (k = 0) is h²p ma²
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