Use a double integral in polar coordinates to find the area A of the shaded region shown below. A = -6 -4 -2 7/2 6 -4 -6 2 r=5 cos 20 4 6 0
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- Find the area in the first quadrant inside the curve r = 4 + cos 2θ but outside the curve r = 3 cos 2θ (see figure), after first finding the intersection points of the two curves.SOLVE THE INTEGRAL DOUBLE SHOWN IN THE PICTURE. (REMEMBER THAT YOU CAN MAKE THE CHANGE FROM COORDINATES TO POLAR COORDINATES)1. Find the area of one leaf rose r=a cos 2B
- Let R be the region inside the polar curve r = 5 + sin 0 and outside the polar curve r = 5 + cos 0 as shown in the figure below. What is the area of R? Use a calculator to evaluate and round to the nearest thousandth.Let R be the region inside the polar curver = -4 cos 0 and outside the polar curve r = 5 +4 cos 0 as shown in the figure below. What is the area of R? Use a calculator to evaluate and round to the nearest thousandth.Find the area of the shaded region. r = 6+5 cos(8) r = sin(2 0)