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The overlap integral between ls atomic orbitals in atoms A and B of a heteronuclear molecule is S = 0.43. A MO-LCAO calculation for the molecule shows that one of the molecular orbitals has the form $(1) 0.223 1sA(1) – 0.877 1sg(2) . Find the normalization constant N for ø. What are the coefficients a and b of the corresponding normalized molecular orbital v(1) = a 1sa(1) + b1sB(2) .

The overlap integral between ls atomic orbitals in atoms A and B of a heteronuclear molecule is S = 0.43. A MO-LCAO calculation for the molecule shows that one of the molecular orbitals has the form $(1) 0.223 1sA(1) – 0.877 1sg(2) . Find the normalization constant N for ø. What are the coefficients a and b of the corresponding normalized molecular orbital v(1) = a 1sa(1) + b1sB(2) .

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter12: The Solid State
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Problem 19PS: Considering only the molecular orbitals formed by combinations of the 2s atomic orbitals, how many...
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The overlap integral between 1s atomic orbitals in atoms A and B of a heteronuclear molecule is S = 0.43. A MO-LCAO calculation for the molecule shows that one of the molecular orbitals has the form $(1) = 0.223 1sA (1) – 0.877 1sB (2). Find the normalization constant N for ø. What are the coefficients a and b of the corresponding normalized molecular orbital v(1) a lsA(1) + b1sB(2) .
Transcribed Image Text:The overlap integral between 1s atomic orbitals in atoms A and B of a heteronuclear molecule is S = 0.43. A MO-LCAO calculation for the molecule shows that one of the molecular orbitals has the form $(1) = 0.223 1sA (1) – 0.877 1sB (2). Find the normalization constant N for ø. What are the coefficients a and b of the corresponding normalized molecular orbital v(1) a lsA(1) + b1sB(2) .
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