The coefficient of static friction between the 100 [N] box and the inclined surface is 0.20. The coefficient of static friction between the rope and the fixed cylinder is 0.10. Determine the force the woman must exert on the rope to cause the box to start moving up the inclined surface. 20°
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- I 00LLJ408 - Go.. Question Info and Solutions Blocks A and B of mass 5 kg and 10 kg respectively are placed on a Smooth inclined plane of Inclination 30, as shown. Block A and B are subjected to forces 5 N And 50 N respectively along the incline, as shown. The coefficient of friction between A andBis 0.50 find the frictional force between A and B in N is: (g= 10 ms SOH 300 Options Solution Fs=Static frictional force umg cos 30 (0.5) (5) (10) cos 30 21.6 N Let a be the acceleration of both the blocks along 5.27 PMA 98N force is needed to push a 45kg box across the wooden floor. What is the value of the coefficient of static friction across the floor and the box? O 0.212 O 0.222 O No answer O 0.122 O 0.012The 500-N block on an incline is acted upon by a force P at an angle from the horizontal. The coefficient of static friction is 0.25. If 0 = 0 deg, compute the value of force P necessary to (a) just start the block up the incline and (b) just prevent motion down the incline. 500 N P
- A box of mass m-20.5 kg is pulled up a ramp that is inclined at an angle 0 17.0° angle with respect to the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.315, and the rope pulling the box is parallel to the ramp. If the box accelerates up the ramp at a rate of a 3.09 m/s, calculate the tension Fr in the rope Use g 9.81 m/s for the acceleration due to gravity. FTThe 121-lb force P is applied to the 250-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate. The friction force is positive if to the right, negative if to the left. Assume μ = 0.45, μk = 0.36. Answer: F= i lbThe 137-lb force P is applied to the 240-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate. The friction force is positive if to the right, negative if to the left. Assume μ = 0.51, Mk = 0.39. P Answer: F = i Mk lb
- moodle.nct.eduom/mod/qi -Learning Portal Courses - Reports - e-Services- Academic Departments - ETC - CIMS - A 17kg crate resting on a horizontal surface is pushed as shown. If the coefficient of static friction u, between the surfaces is 0.24, what is the minimum force (F) required to start the motion? O a 4.08N O b. 70.83N Oc 39.98N Od. 694.17N Windows buut An object of mass Skg is sliding with a constant velocity of 10m/s on a frcitionless horizontal table. The force needed to keep the object moving with the same velocity is. 144 4- # 4. 6. V.You are climbing on a hill that is inclined at 15° with the horizontal and you wish to build a rope tow to pull yourself up. Ignoring friction, calculate the tension you needed on the rope to give your body that has a mass of 45kg at 1.5 m/s^2 acceleration. What if you are to consider the friction of 100N, what is the value of the tension and coefficient of friction?You are trying to slide a heavy trunk across a horizontal floor. The mass of the trunk is 85kg, and you need to exert a force of 3.3*10^2 N to make it just begin to move. a)Determine the coefficient of static friction between the floor and the trunk.b)After the trunk starts moving, you continue to push with this force. The trunk reaches a speed of 2.0m/s after 5.0s. Calculate the acceleration of the trunk if the coefficient of kinetic friction between the trunk and the floor is 0.32.
- A 45 kg box is at rest at one end of a 2 meter board. That end of the board is slowly raised at an incline until the box starts to slide. At that point, the angle is at 34 degrees. The coefficient of kinetic friction is 0.50N. Please help me calculate the coefficient of static friction between both the box and the board?In the figure, the block of mass 2.00 kg accelerates down the inclined plane. The coefficient of kinetic friction is 0.200 and angle of the inclined plane is 30.0°. What is the acceleration of the block? normal force N friction force f mg sine mg cose mg O 3.05 mis? O 5.05 m/s? O 2.05 m/s? O 4.05 m/s?A block of mass M slides (3) along a rough (a) inclined surface (Ja au) with a constant velocity. The inclination angle ( ) of the surface is e as shown in the adjacent figure ). The coefficient (J) of kinetic friction (H ) of the Time left 059:40 inclined surface is: A. cos (e) B. tan(0) C. sin(20) M V- Constant D. cos(0) E. sin(e) *Take g= 9.8 m/s