Suppose you are interested in the rate of autism among current school-aged children in Utah. You collect a sample of 400 children between the ages of 5 and 18 and find that two have had a previous diagnosis of an autism disorder. You plan to calculate a 95% confidence interval estimator of the proportion of school-aged children in Utah who have ever had a diagnosis of an autism disorder. Which of the following is the most likely reason you would use a Wilson estimator to calculate the confidence interval estimator? A confidence interval estimator based on the Wilson estimator does not use the normal distribution.   It is possible that if even the actual proportion in Utah is 1%, your sample may only have very few children who have had a previous diagnosis of an autism disorder.   It is an easier way to calculate the confidence interval estimator.   It is uncomfortable to define having been diagnosed with autism as a success.     Let p be the proportion of school-aged children in Utah who have ever had a diagnosis of an autism disorder. Using the Wilson estimate, the 95% confidence interval estimate of p is0.0099    ±     . (Hint: For a 95% confidence interval estimate, use zα/2zα/2 = 1.96.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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ISBN:9780079039897
Author:Carter
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Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
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Suppose you are interested in the rate of autism among current school-aged children in Utah. You collect a sample of 400 children between the ages of 5 and 18 and find that two have had a previous diagnosis of an autism disorder. You plan to calculate a 95% confidence interval estimator of the proportion of school-aged children in Utah who have ever had a diagnosis of an autism disorder.
Which of the following is the most likely reason you would use a Wilson estimator to calculate the confidence interval estimator?
A confidence interval estimator based on the Wilson estimator does not use the normal distribution.
 
It is possible that if even the actual proportion in Utah is 1%, your sample may only have very few children who have had a previous diagnosis of an autism disorder.
 
It is an easier way to calculate the confidence interval estimator.
 
It is uncomfortable to define having been diagnosed with autism as a success.
 
 
Let p be the proportion of school-aged children in Utah who have ever had a diagnosis of an autism disorder. Using the Wilson estimate, the 95% confidence interval estimate of p is0.0099    ±     . (Hint: For a 95% confidence interval estimate, use zα/2zα/2 = 1.96.)
 
 
 
 
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