Suppose you are given the following five pairs of scores: X Y 3 1 4 2 6 3 2 4 10 10 Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right corner of the tool, and drag it to the appropriate location on the grid. > 10 9 8 7 6 5 + ? Based on your scatter diagram, you would expect the correlation to be positive The mean x score is Mx = and the mean y score is My = Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores Deviations × Y X - Mx Y - MY 3 1 4 2 60 3 2 4 10 10 Squared Deviations Products (X-MX)² (Y - MY) 2 (X-MX) (Y - MY) The sum of squares for x is SSX = The sum of squares for y is SSy = The sum of products is SP = Because the sign of the sum of products is The correlation coefficient is r = the sign of the correlation coefficient Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be because

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.1: Stem-and-leaf Plots And Histograms
Problem 12E
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Suppose you are given the following five pairs of scores:
X
Y
3
1
4
2
6
3
2
4
10
10
Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the
upper right corner of the tool, and drag it to the appropriate location on the grid.
>
10
9
8
7
6
5
+
?
Transcribed Image Text:Suppose you are given the following five pairs of scores: X Y 3 1 4 2 6 3 2 4 10 10 Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right corner of the tool, and drag it to the appropriate location on the grid. > 10 9 8 7 6 5 + ?
Based on your scatter diagram, you would expect the correlation to be positive
The mean x score is Mx =
and the mean y score is My =
Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the
squares of the deviations, and the products of the deviations.
Scores
Deviations
×
Y
X - Mx
Y - MY
3
1
4
2
60
3
2
4
10
10
Squared Deviations
Products
(X-MX)² (Y - MY) 2 (X-MX) (Y - MY)
The sum of squares for x is SSX
=
The sum of squares for y is SSy
=
The sum of products is SP =
Because the sign of the sum of products is
The correlation coefficient is r =
the sign of the correlation coefficient
Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be
because
Transcribed Image Text:Based on your scatter diagram, you would expect the correlation to be positive The mean x score is Mx = and the mean y score is My = Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores Deviations × Y X - Mx Y - MY 3 1 4 2 60 3 2 4 10 10 Squared Deviations Products (X-MX)² (Y - MY) 2 (X-MX) (Y - MY) The sum of squares for x is SSX = The sum of squares for y is SSy = The sum of products is SP = Because the sign of the sum of products is The correlation coefficient is r = the sign of the correlation coefficient Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be because
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