Q5. Using the pK values of the conjugate acids of the leaving groups (pK perp (HBr) = - 9 . pK (H,O)-15.7. PK (HO) -1.7.), explain the difference in reactivity in substitution reactions between: a. CH,Brand CH,OH b. CHOH, and CH,OH Please answer correct.

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Q5. Using the pK values of the conjugate acids of the leaving groups (pK perp (HBr) = - 9 . pK (H,O)-15.7. PK (HO) -1.7.), explain the difference in reactivity in substitution reactions between:

a. CH,Brand CH,OH

b. CHOH, and CH,OH

Please answer correct.!!

 

Q5. Using the pk, values of the conjugate acids of the leaving groups (pK (HBr)--9, pK, (H₂O)-15.7.
pk (H,0)=-1.7,), explain the difference in reactivity in substitution reactions between:
a. CH,Br and CH,OH
b. CH,OH, and CH,OH
Transcribed Image Text:Q5. Using the pk, values of the conjugate acids of the leaving groups (pK (HBr)--9, pK, (H₂O)-15.7. pk (H,0)=-1.7,), explain the difference in reactivity in substitution reactions between: a. CH,Br and CH,OH b. CH,OH, and CH,OH
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