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- ? ReviewQUESTION 1 Determine the reaction moment at x = 0 in kN-m. QUESTION 2 Determine the vertical reaction force at x = 0 in kN. QUESTION 3 (1-3) Determine the horizontal reaction force at x = 0 in kN. The distributed load, f(x), is equal to 100 kN/m. /// f(x) 3 m24 - In the cage system connection in the figure; Rod forcesS1= 100 kN,S2= 40 kN,S3= - 60 kN,S4= 50 kN,If S5= 80 kN, Calculate the resultant force acting on joint point D.If the vector representation of the resultant force is R= Rx i + Ry j, Rx = ? Note: The (-) sign of the rod force S3 indicates that the force is pressure. A) 42.43B) -36.36C) -12.93D) 3.64E) 36.36
- Determine the internal normal force at point C. Take F1F1F_1 = 460 lblb , F2F2F_2 = 250 lblb , F3F3F_3 = 346 lblb . Determine the shear force at point C. Determine the moment at point C. Determine the internal normal force at point D. Determine the moment at point D.For the beam shown, find the reactions at the supports and plot the shear-force and bending-moment diagrams. V = 7 kN, V2 = 7 kN, V3 = 100 mm, and V4 = 1300 mm. (mm) 0 Provide values at all key points shown the given shear-force and bending-moment diagrams. X (mm) A C V2 B E D F 0.00 +V Reaction force R₁ (left) = In the shear-force and bending-moment diagrams given, 0.00 X (mm) kN and reaction force R₂ (right) = P KN. 0.00Draw the shear force and bending moment diagram for the loaded beam shown below. Also mark the salient points in the diagram. where F=20 N, F2=70N, F3=80N, a=3m, b=2 m, c=6m & d=2m. Neglect the self weight of the beam. F1 F2 F3 b Shear force at the point "B" = N) (unit in The Reaction at the support "A" RA (Unit in N) is The Reaction at the support "B" Rg (Unit in N) is Bending Moment with respect to "B" = (unit Nm) Shear force at the point "A" = N) Bending Moment with respect to "E" = (unit Nm) (unit in Shear force at the point "C" = _ (unit in N) Bending Moment with respect to "D" = (unit Nm) Bending Moment with respect to "C" = (unit Nm) Shear force at the point "D" = N) (unit in Bending Moment with respect to "A" = (unit Nm) Shear force at the point "E" = N) (unit in
- estion 12 Find the moment about B and D for the loaded section as shown in figure. The forces F1 =10 N, F2 = 50 N, F3 = 28N, F4 =30 N. AB =14 m, BC=10m, CD = 9 m, 0, =45°. ot yet nswered (ENTER ONLY THE VALUES BY REFERRING THE UNITS GIVEN I | BRACKET. ALSO SUBMIT THE HAND WRITTEN ANSWER SHEET IN THE LINK PROVIDED) arked out of 00 F3 Flag Jestion F4 D F2 O The moment about 'B' (in Nm) = (i) The moment about D' (in Nm) =X Z d₁ BExample 1- determining the components of the specified forces in the direction of the x and y axes numerically + y F1x = F1 cos a, = 400N cos 45 = 282,8N F2x = F2 cos a, = 200N cos 130 = -128,6N F3x = F3 cos oaz = 300N cos 220 = - 229,8N Fax = F4 cos a= 350N cos 45 = 0 N %3D F: F1 + X F3 = F1 sin a, = 400N sin 45 = 282,8 N F4 %3D %3D 1y F = F2 sin a, = 200N sin 130 = 153,2 N %3D 2y F3y = F3 sin a, = 300N sin 220 = - 192,8 N Fay = F4 sin a, = 350N sin 270 = - 350 N %3D -y
- 3-4 Sketch a free-body diagram of each element in the figure. Compute the magnitude and direction of each force using an algebraic or vector method, as specified. F=400 N. 30° B 60° 2 1.9 m 0 9 m C D 60° E xwith the following modifications: Add an additional force P = 20kN acting downwards at point BDraw the shear force and bending moment diagram for the loaded beam shown below. Also mark the salient points in the diagram. where F1=80 N, F2=70N, F3=80N, a=3m, b=3 m, c=5m & d=5m. Neglect the self weight of the beam. F3 F2 F1 VD (Enter only the values in the boxes by referring the unit given in brackets. Also upload your hand written answers in the link provided) The Reaction at the support "A" RA (Unit in N) is The Reaction at the support "B" Rg (Unit in N) is Shear force at the point "A" = (unit in N)