Molar mass pf Ca (IO3)2 =40+2 (126+3 (16)) =40+2(126+48) =40+2 (174) = 40+348 =388g/mol Mass of Ca(IO3)2 produced = moles x molars mass of Ca (IO3)2 = 0.01875 x 388g= 7.275g w ww w (cWhat is the percent yield if the actual yield of Ca(IO,), is 6.72 g ?

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Analytical Tools

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