In making wine, glucose (C6H12O6) is fermented to produce ethanol (C2H5OH) and carbon dioxide (CO2) as shown in the reaction. a. If the fermentation reaction starts at 53.2g glucose, what is the theoretical yield of ethanol in grams? b. If 25.8g ethanol is produced, what is the percent yield of the reaction? C6H12O6 -> 2 C2H5OH + 2 CO2 Molar mass of C6H12O6 = 180.156 g/mol Molar mass of C2H5OH = 46.07 g/mol Molar mass of CO2 = 44.01 g/mol
In making wine, glucose (C6H12O6) is fermented to produce ethanol (C2H5OH) and carbon dioxide (CO2) as shown in the reaction. a. If the fermentation reaction starts at 53.2g glucose, what is the theoretical yield of ethanol in grams? b. If 25.8g ethanol is produced, what is the percent yield of the reaction? C6H12O6 -> 2 C2H5OH + 2 CO2 Molar mass of C6H12O6 = 180.156 g/mol Molar mass of C2H5OH = 46.07 g/mol Molar mass of CO2 = 44.01 g/mol
Chemistry for Engineering Students
3rd Edition
ISBN:9781285199023
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.77PAE: The pictures below show a molecular-scale view of a chemical reaction between H2 and CO to produce...
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In making wine, glucose (C6H12O6) is fermented to produce ethanol (C2H5OH) and carbon dioxide (CO2) as shown in the reaction.
a. If the fermentation reaction starts at 53.2g glucose, what is the theoretical yield of ethanol in grams?
b. If 25.8g ethanol is produced, what is the percent yield of the reaction?
C6H12O6 -> 2 C2H5OH + 2 CO2
Molar mass of C6H12O6 = 180.156 g/mol
Molar mass of C2H5OH = 46.07 g/mol
Molar mass of CO2 = 44.01 g/mol
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