If the H colored red is eliminated as H*, then two possible diastereomers can form. Draw the curved arrows for this electrophile elimination step, and draw each of the diastereomeric products. H He H20 + H3C-C-c~CH3 H
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- Draw the appropriate curved arrows and products for each set of reactants undergoing a coordination step. Identify each reactant species as a nucleophile or electrophile. (a) NH₂ + AICI, →? (b) H₂O + BF₂? (c) ³0° H₂C OH - >?Draw curved arrows to show the movement of electrons in the step of the mechanism shown below. Arrow-pushing Instructions X→UU :0: :O: || CH3-C-CH₂-C-OEt :OEt :O: || :0: || CH3-C—CH—C—0—OEt + EtO: HDraw the products of the reaction shown. Electron flow is indicated with curved arrows. H₂C CI:
- The two pentene isomers react with mCPBA, followed by an aqueous workup with NaOH/H2Ó. Draw the key reaction intermediates and the product(s); use arrow pushing to explain the stereochemical outcomes of the reactions Intermediate Final Products MCPBA CO2OH mCPBA NaOH/H2O CI Intermediate Final Products MCPBA NaOH/H2O 6.If the anionic species shown were to eliminate a leaving group, the three possi- bilities would be H3C¯, CI, or CH30¯. Draw the curved arrow notation and the products for each of these elimination steps. Which is the major product? Why? CICurved arrows are used to illustrate the flow of electrons. Follow the arrows and draw the intermediate and product in this reaction. Include all lone pairs. Ignore stereochemistry. Ignore inorganic byproducts. Draw Intermediate CH₂OH₂* protonation H₂C CH3OH₂* protonation CH3OH deprotonation loss of H₂O elimination Draw Intermediate CH₂OH nucleophilic addition || Draw Intermediate CH3OH deprotonation Draw Product
- Draw the final product of this series of reactions. |||** OH 1. SOCI₂ 2. NaCN • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • If more than one product is possible, only draw the major product. • If the reaction produces a racemic mixture, draw both stereoisomers.s sugar X a reducing or a non-reducing sugar? Reducing, because one/both of the rings can open to expose a free aldehyde group Non-reducing, because one/both of the rings can open to expose a free aldehyde group Reducing, because neither of the rings can open to expose a free aldehyde group Non-reducing, because neither of the rings can open to expose a free aldehyde group Reducing, because one/both of the rings can open to expose a free ketone group Non-reducing, because one/both of the rings can open to expose a free ketone group Reducing, because neither of the rings can open to expose a free ketone group Non-reducing, because neither of the rings can open to expose a free ketone group Cannot be determined from the structure shownDraw the products of the following reactions, indicating both regiochemistry and stereochemistry when appropriate. Use wedge and hash bonds ONLY when needed to show reaction stereochemistry. In cases where there is more than one answer, just draw one.
- Alkene bromination. The two butane isomers react with Br2. Draw the key reaction inter- mediates and the product(s); use arrow pushing to explain the stereochemical outcomes of the reactions Final Products Intermediate Br2 Intermediate Final Products Br2If Hj is eliminated from the carbocation shown here in an electrophile elimination step, then three possible constitutional isomers can form. Draw the mechanism for the formation of all three of those products. H20 +Question 5 1). Draw all resonance structures for the carbocation intermediate formed by para attack; circle the resonance structure that is particularly unstable. N- N Cl₂ AICI 3 H 2). Draw all resonance structures for the carbocation intermediate formed by ortho attack; circle the extra resonance structure that is particularly stable. H a Aer ANSAS C HNO3 H₂SO4