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A: Solution is following in explanation step.
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- 1. Solve for the orthogonal trgsctories y² = 4x*(1- kx) %3DThe number of defects on the front side (X) of a wooden panel and the number of defects on the rear side (Y) of the panel are under study. Suppose that the joint pmf of X and Y is modeled as fxy (x,y)=c(x+y), x=1,2,3 and y=1,2,3. Check if the number of defects on the front side (X) of a wooden panel and the number of defects on the rear side (Y) of the panel are independent.2. Estimate the solution of 3x? = ex + 2 with po = 1, p1 = 1.8 using SECANT METHOD. Find 2 %3D %3D Iterations.
- 1. у%3D х3 — 2х2 + 3х — 5 y = 3 – 2x² + 3x – 5 dy - Зx2 — dx 4x + 3Your answers are saved automatically. Remaining Time: 1 hour, 19 minutes, 10 seconds. v Question Completion Status: A Moving to another question will save this response. Question 1 If y = u3 -4 and u = 3x2 + 10 , find y' %3D %3D O 3x(6x2 + 10)2 O 6x(3x2 + 10)2 O 18(3x2 + 10)2 18x(3x2 + 10)2 A Moving to another question will save this response. axerSolve the orthogonal trajectories of the problem
- Ify %3D (x + 1)(2х -), then y' will be A. (x + 1)(2 – V) + (2x -) В. (х+ 1) + (2х-v)(2 — Vx) 1 c. (x+1)(2- + (2x – v3) х+ 1) (2 + (2х — Vx) С. D. (x+1)(2– D. (x+ 1)(2 + [2х 2Vx/ 2VxNote: Give me right solution with clear steps. Given the data points; (2,5),(3,1),(5,2),(6,0) and (7,3),indicate ln(y-C1) =C2+ln x using Least square methodA student solves an optimization problem as in Model 1, except that in the problem Mini and Max are given 800 feet of caution tape. Examine the student's solution, explain what they did wrong, and write down what the student should have done instead. Student Solution (find the error): A=xy P = 2x+2y = 800 400 - x = y A = x (400-x) = 400 x - x² A'(x) = 400 2x, so x = 200 is a critical number. Check the endpoints (x = 0 and x = 400) and critical number: A'(0) = 400; A'(200) = 0; A'(400) = -400. Therefore the maximum area is 400 square feet.