Find current i, and voltage v, in the circuit. а 0.5i, A ЗА
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- Required information A 256-V rms 60-Hz supply serves a load that is 10 kW (resistive), 15 KVAR (capacitive), and 22 KVAR (inductive). 6 Find the current drawn from the supply. The current drawn from the supply is 4 AQI// Analysis the circuit shown in figure below. SET J2 Q2 CLK K2 X RESET SET J1 Q1 CLK K1 RESET CLK •A 200 load receives power from parallel-connected battery cells, as shown in the figure below. Determine the terminal voltage of the parallel- connected battery cells. r1 -r2 1 Ohm 1 Ohm -R_LOAD 20 Ohms V1 V2 12 V 12 V 11.6954 V 10.8875 V 11.7073 V 10.6543 V ww
- Use the following constants if necessary. Coulomb constant, k = 8.987 x 10° N - m² /C2. Vacuum permitivity, co = 8.854 x 10 12 F/m. Magnetic Permeability of vacuum, Ho = 12.566370614356 x 10-' H/m. Magnitude of the Charge of one electron, e = -1.60217662 × 10–19 C. Mass of one electron, me = 9.10938356 x 10 31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means micro coulomb. a R5 R3 e R9 R, R6 R8 Ry K Suppose you have the following circuit diagram. Here R1 =1.1 kN, R2 = 3.3 kN, R3 = 2.2 kN, R4 = 22 kN, R5 = 22 kN, Rg = 11 kN, R7 = 11 kN, Rg = 11 kN, R9 = 1.1 kN are the resistances on the circuit where kN stands for kilo ohm. The electromotive forces of the batteries are & = 5 volts and Ez = 3 volts. a) Calculate Rik. the resistance equivalent to R5, Re, R7, Rg and R9 between the terminals b and k. Value of Rhk Give your answer to at least two significance digits. Ω b) Calculate the current through R1.Find current I, in the circuit of Figure Q2(b). j62 10 Q :20 j12 V 12 2 j20 10/80° A Figure Q2(b)(a) Use Ohm's Law to derive an expression relating Vout to Vin using the values of the two resistors. For this calculation, assume that you have no load attached (i.e. RL → xx). Make sure to explain in words each step you take. Hint: Vout is just the voltage drop across R2. You can draw in a battery with AV = Vin if that helps you set up the relationships. R1 Vin R2 Vout (O Vin- Your answer should be in the form, Vout The term in parentheses is called the gain of the divider, or the divider ratio. in· ww
- E D AV = 6.00V C R B AV 5.00V 0.300A A 3.000 18. ΦΩ 32. ΦΩ F G Use the junction rule for currents and AV-IR as needed to solve for the currents in the other resistors and the value of the unknown resistor R. Proceed as in class, starting with point A at zero volts. Hint: eventually you will find an elevation which is negative, meaning that point A is not actually the lowest elevation in the circuit.TOPIC: Fundamentals of Alternating Current Powers Give illustration and a step by step solution. Final answer must be in 4 decimal places. 1. A load takes 55kW at 70% power factor lagging from a 240V, 50Hz supply. If the supply is made 60Hz, with the voltage remaining the same, what will be the kW load at 60Hz? 2. An inductive coil takes a current of 2A and consumes 160W when connected to a 240V supply. A second coil when connected across the same supply takes 3A and 500W. Find the total power when the two coils are connected in series to the supply. 3. A series RC circuit is connected to 230V, 60Hz source. If the power taken by the circuit is 4,800W and the voltage drop across the resistor is 115V, calculate the capacitance of the capacitor. Thank You in advance!https://docs.goog X p tabs together, right-click a tab z5bCAq361TACoM7x7Q/formResponse R= 3 Ohm Vs- 12 v O Got it Remind me later Q6: For the following circuit, find the total resistance between points A,B (Reg) and the total current from point B to A if the applied voltage VAB equal 30 v ww 152 22 102 G F 20 2 10 2 40 S2 30 2 ww Reg 6 Ohm It= 5 AO Reg =4.5 Ohm It= 6.66 A Reg 3 Ohm It= 10 A Reg -6 Ohm It= -5 AO none of the mentioned ABE www