Fill in the catalytic intermediates and provide number of electrons and provide oxidation state of the metal PPh Pd. PPh PhyP Pphg PPhg ligand dissociation 2 PPhy OMe product Ph,P-Pd-PPhg electron count: oxidative addition reductive elimination oxidation state: electron count: transmetallation KOIBU NH
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- The metal to ligand interaction in a transition metal allyl complex comprises of, (41 and Y2 MOs are doubly occupied; Y3 is unoccupied) * O W1 -M (s), interaction. 42 - M (p), interaction. Y3 - M (p) interaction. O 43-M (s) interaction.The coloriesS supe atanliquid was so 11. How does the addition of H3O* affect the following reaction equilibrium? 2CrO42- (aq, yellow) + 2H3O* (aq) -> Cr2O7²- (aq, orange) + 3H2O (1) a. The reaction shifts to the right and the concentration of CrO42- increases. b. The reaction shifts to the right causing the concentration of Cr2072 to decreases and the solution to turns yellow. c. The reaction shifts to the right resulting in a reduction in the concentration of H3O* and an increase in the concentration of Cr2O,2. d. The reaction shifts to the left and the concentration of CrO42 increases. e. The reaction shifts to the left and the concentration of CrO42 decreases.(a) Give the formal oxidation number and the d-electron count of the transition element and the total number of valence electrons in metal complexes A - E. A Li*[AuMe4] B V(15-Cp)₂Cl2 C Ta(15-Cp)2(=CH₂)Me D Pd(PPH3)4 E ZnMe2
- Give the synthesis pathway to synthesize the complex of trans-[PtCl2(en)(tu)] (structure below) by given the trans effect order is tu > Cl > NH3. CI H2N, H, ...N H,N N. H2 CI H2N tu = thiourea H2N5) Consider the rhodium complex below. Reaction with 1 equivalent of oxygen gas oxidizes the metal centre and gives a new complex with cis, distorted octahedral geometry. Draw the structure of the product and give the oxidation state, valence electron count, and d-electron count for both rhodium complexes. Ar 1 eq. O2 Ph3P. Rh Ph3P -"Bu ?Which of the following lignads is ( are ) considered as chelate ligand acac phen en trien O all of them
- Vanadium (V) can be reduced to vanadium (IV) by reaction with a “Jones redactor,” a Zn-Hg amalgam. The reactions of interest are:VO2 + + 2H+ + e- -->VO 2+ + H2O E⁰ = + 1.00 VZn 2+ + 2e- -->Zn E⁰ = - 0.76 VCalculate E⁰ and ∆G⁰ for the reaction.15. Earth abundant Ni compounds with appropriate ligands have been reported to catalyze C- C bond forming reactions like Palladium and other precious metals. Below are Ni complexes that have two common oxidation states for this metal. For each metal complex: Provide the oxidation state of the metal center, the d-electron count of the metal, and the total number of valence electrons around the metal. f fif Ni...... oxidation state: oxidation state: d-electron count: d-electron count: total electron count: total electron count:. For the following organometallic complexes, determine the metal oxidation state, the metal d electron count, and the overall complex electron count. a. OC. OC Re CH3 b. e. Ph3P Ph3P OC. OC Pd PPh3 CH3 H. PPh3 C. f. OC OC Et3P Et3P PPh3 Fe PPh3 PEt3 CO PEt3
- The Hybridization in [Ni(CN)4]2 is.. а. sp3 b. dsp? С. d²sp² d. d²sp³ CLEAR MY CHOICE1. Arrange the following in order of increasing molar absorptivity ɛ, and explain your ordering. a. A d-d transition in [Fe(H2O)6]* b. A d-d transition in [FeCl4] I. c. A d-d transition in [Ni(H2O)6]** d. A d-d transition in [VCL4]²-6. C3H&M(CO); (M: transition metal) complex obey the 18 electron rules. Draw two possible structure for values of hapticity : 4 and 6, respectively and predict suitable metal atom(s)