F = 250 lb - 30°, 45 F2 = 375 lb
Q: (M=450 lb-ft (M)s = 300 lb-ft 3.5 ft 1.5 ft 2 ft 2 ft (Mh = 250 lb-ft
A:
Q: 150 lb/ft A В -6 ft -8 ft
A: Let us draw the reaction at the supports Weight of the rectangular load = 150 lb/ft(8ft)=1200 lb…
Q: Q2:- In figure ax-4.903 m/s, ay3=9.806 m/s*.Find the pressure at A,B,and C as shown in fig.2
A: Given data, Acceleration in x-direction, ax = 4.903 m/s2 Acceleration in y-direction, ay = 9.806…
Q: 2. Based on the figure below: a. Setup the equations to solve the problem. b. Determine R1 and R2.…
A: It is required to determine support reaction for given loading
Q: -C-((3/4)*D)))-A)/2 C-((3/1)*D)-A)/2
A: Given, A+2B = 5C-3/4D A= [20 22;4 1;6 1]C= [10 10;5 5 ;2 2]D = [1 1;1 1;1 1]B=…
Q: 600 lb-ft B 350 lb-ft 3ft 1 ft 500 lb-ft 2 ft
A: For solution refer below images.
Q: Engine has a capacity of 20 milliliters per cylinder and the length of the axle arm is 5 cm Find the…
A:
Q: 100 lb B 12а++ - 4 ft - 80 lb - 3 1 -
A: To find : The shear stress in the beam. Free body diagram : The free body diagram is shown below:…
Q: F2 = 500 lb %3D F1 = 200 lb 3 1 60° 70° F3 = 800 lb 45° A
A: GIVEN DATA A FORCE SYSTEM GIVEN WE HAVE TO FIND THE RESULTANT OF FORCE
Q: 350 lb 30 250 lb
A:
Q: Neglecting the mass of the beam, compute the reactions at A and B
A:
Q: |s0o0 FiG. P 1-10 1-10. Resolve the 300-lb force acting on body OBC in Fig. P 1-10 into two…
A:
Q: Q2:- Three unbalanced masses (2 Ib), (3 Ib) and (4 Ib) are arranged as shown in the Fig. below. It…
A: Given Masses = 2 lb, 4lb, 6 lb To find Balanced mass
Q: The coefficient of friction everywhere is 0.30. If max force P at static equilibrium is 55N, find…
A: Solution: Considering the weight acts at the midpoint of the ladder, then Considering static…
Q: 200 lb/ft 800 lb 37 A Bカ 1 5' 4' 21 21
A: I HAVE FULL EXPLAINED BUT IF YOU WANT ONLY BX DIRECTLY GO FOR SECOND STEP
Q: Q2:- In figure ax=4.903 m/s, ay-9.806 m/s".Find the pressure at A,B,and C as shown in fig.2
A:
Q: Find PC given that PA is 2900 lb/ft2 a. 2312 lb/ft2 b. 3149 lb/ft2 c. 4365 lb/ft2 d. 1631 lb/
A: The density of water in English units is Since the density of air is very less, its head can be…
Q: F = 500 lb Determine the components ofF, and F, in x-y and x’-y’ systems 25 450 30 F2 = 750 lb
A:
Q: 2 kN 50 mm 5 kN• m D 80 mm B C 1.0 m 1.0 m 1.0 m
A:
Q: 3000 lb 90 Ib /ft 9 ft 200 lb/ft
A: For solution refer below images.
Q: 13378.2898 lbm to lbf
A:
Q: 18 kN 3 B 25 kN 8m DE 6m D 10 kN Figure 1
A:
Q: 100 lb 30° 200 lb 2 ft 300 ft-lb 2 ft 2 ft 2 ft-
A: First we resolved 100 lb force, and calculated horizontal force, vertical force and moment due to…
Q: 1.5 m 4 kN A B 2 m 8 kN C D 2 m F E
A: Let RFx and RFy are the horizontal and vertical reaction at F RE is vertical reaction at E By using…
Q: where did u get 2088.54lb/ft^2 and 0.07488 lb/ft^3??
A:
Q: 400 lb F1 = 400 j F2 = -600 k 37 F3 = 500 sin 45 i -500 cos 45 k 3 7* r2=? 600 lb 45 M- rixF,, M,-…
A: Calculate the given position vectors. r1=3 i^+10 k^ inr2=6 i^+3 j^+7 k^r3=6 i^-3 j^+ 7 k^
Q: In the Figure 6, the absolute force value in the bar AC is (in kN): Figure 6: 5 m/ 5 m 5 m A 20 KN B
A:
Q: In each case, draw the shear and moment diagrams for the beam.
A: The free body diagram of the first beam is as follows: Calculate the force in the vertical…
Q: - 2- 45 100lbs/ft 300lb 30 200lbs
A:
Q: Force in the cable CD in Newton
A: Draw the free body diagram of the joint C.
Q: Find Pc given that Pa is 2900 lb/ft^2 a. 3149 lb/ft2 b. 4365 lb/ft2 c. 2312 lb/ft2 d. 1631…
A:
Q: /Find the two forces Fbc & Fac as shown * :in the figure below Fab=30 N Fbc
A: Given:Fab=30 N
Q: a)P2, b)delta H, c)delta U,
A: As per our company guidelines we are supposed to answer only first 3 sub parts in case of multiple…
Q: Find the result of ( F1) Force acting as shown below?
A: Solution:
Q: figure. 400 lb 30 Note: 1" x 1" 228 lb
A: To find resultant
Q: Select one: a. k = 7.8 lb/in %3D b. k = 4.8 lb/in %3D c. k = 5.8 lb/in %3D d. k = 6.8 lb/in %3D
A: Solution : Given data : weight = 10lb unstretched length = 8 in…
Q: Define the following terms: Weight Tension Friction Equilibrium
A: GIVEN DATA- SOME TERMS GIVEN WE HAVE TO DEFINE IT
Q: Q2:- In figure ax=4.903 m/s , ay=9.806 m/s².Find the pressure at A,B,and C as shown in fig.2 ay 300…
A: Givenax=4.903m/s2ay=9.806m/s2
Q: 5 kN 4 m B 5 kN 4 m C D 2 m
A: The free-body diagram of the strut is given as,
Q: 2 kN/m 10 kN t. 5 m 3 m 2 m Figure 2
A:
Q: 2-18 Refer to Fig. P2–18. Prove that the x and y components of a force acting in a direc- tion…
A: 2-18) The inclination of the Force F can be given by - cosθ=hh2+v2, sinθ=vh2+v2Therefore -Fx = Fcosθ…
Q: 1500 lb 300 lb/ft 300 lb/ft A B 3 ft- 3 ft- HINGE ROLLER (2)
A:
Q: In the Figure 6, the absolute force value in the bar AC is (in kN): Figure 6: 5 m 5 m A 20 KN 5 m B
A: FAC = 23.0940 kN
Q: -9. Determine the resultant force on the lever shown in Figure P2-9. 20° 20 lb 30 lb FIGURE P2-9
A: Draw the free body diagram as ,
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- F = 600 lb; 5 120° 60° F2 = 400 lbIn the diagram, if the 200 lb is A, 350lb is B and 250 lb is C, what is the magnitude of the resultant force? R= A-BWhen a stationary mass of gas was compressed without friction at constant pressure its initial state of 0.8 m3 and 0.105 MPa was found to change to final state of 0.40 m3 and 0.105 MPa. There was a transfer of 85 kJ of heat from the gas during the process.How much did the internal energy of the gas change ? * 1 Add File
- The pipe assembly of the figure is supported by a fixed support at point A. A couple-moment and a force are applied at points B and C, respectively. In Cartesian coordinates, the applied couple-moment is MB = -150 k N-m, and the applied force is Fc = + 200ĵ Newtons. You may neglect the weight of the pipe assembly. 1. Draw a FBD which is suitable for solution of this problem, when seeking the unknown force and moment reactions at the fixed support, Point A. You may use the existing drawing given below. Your FBD must clearly/correctly show the force and moment reaction vectors. Use double arrowheads to distinguish moment vectors from force vectors. 2. Calculate F°MA, which is the moment generated at A due to the force applied at Point C. 3. Write the equations of equilibrium and solve to find the reactions at Point A. Specifically, find the force-reaction vector, A and the moment-reaction vector, *MA-The cross-section at C is annular, having an outer diameter of 25mm. The 1200 N forces are applied and the normal stress in the bone at point C is determined to be 3.80 MPa. Calculate the inner diameter of the bone cross section at C.If the specific weight of a liquid is 58.5 lbf per cubic foot, what is the specific volume of the liquid? 0.18 slug /ft³ 0.23 slug /ft³ 0.38 slug /ft³ O 0.55 slug /ft³