d) For the circuit shown in figure Q3d use the superposition principle to find the current through the 500 2 resistor. 50 V + 100 Ω 75 V + 200 Ω 400 Ω 200 Ω Figure Q3d 500 Ω 10 considening sov Source: Va Vb 500 Consider SOV source: KCC @node !! Va - so Va Vα- Vb 0 + 2001 100 200 500 1000 200- 4001 scva-50) 2.5 Va Va - Vb + t = O 500 500 500 + SO Consider 75 Vsource: va 500 л Vb sva-50) + 2.5va + Va-vb 0 Sva -250 +2.5va +va - Vb = 0 8.5va-vb-250 = 0 8.5Va-Vb = 250 4CL node 1 2000 1000 200 л 400~ Na Va Va-vb = 0 + t 75V 100 400 500 node 2: Vb-Va 500 Vb Vb - 75-0 t 400 200 Vb-va + 1.25V b + 2.5 cub-75) Soo 500 500 CVb-va) +1.25 Vb + 2.5 (vb-73) = 0

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Please answer the below question explaining each step 

Solve using nodal analysis (preferably) and please see whether my working for nodal analysis is correct or not

 = 0.0238A from A to B 

d) For the circuit shown in figure Q3d use the superposition principle to find the
current through the 500 2 resistor.
50 V
+
100 Ω
75 V
+
200 Ω
400 Ω
200 Ω
Figure Q3d
500 Ω
10
Transcribed Image Text:d) For the circuit shown in figure Q3d use the superposition principle to find the current through the 500 2 resistor. 50 V + 100 Ω 75 V + 200 Ω 400 Ω 200 Ω Figure Q3d 500 Ω 10
considening sov Source:
Va
Vb
500
Consider SOV source:
KCC @node !!
Va - so
Va
Vα- Vb
0
+
2001
100
200
500
1000
200-
4001
scva-50)
2.5 Va
Va - Vb
+
t
= O
500
500
500
+
SO
Consider 75 Vsource:
va
500 л
Vb
sva-50) + 2.5va + Va-vb
0
Sva -250 +2.5va +va - Vb = 0
8.5va-vb-250 = 0
8.5Va-Vb = 250
4CL
node 1
2000
1000
200 л
400~
Na
Va
Va-vb = 0
+
t
75V
100
400
500
node 2:
Vb-Va
500
Vb
Vb - 75-0
t
400
200
Vb-va +
1.25V b
+
2.5 cub-75)
Soo
500
500 CVb-va) +1.25 Vb + 2.5 (vb-73) = 0
Transcribed Image Text:considening sov Source: Va Vb 500 Consider SOV source: KCC @node !! Va - so Va Vα- Vb 0 + 2001 100 200 500 1000 200- 4001 scva-50) 2.5 Va Va - Vb + t = O 500 500 500 + SO Consider 75 Vsource: va 500 л Vb sva-50) + 2.5va + Va-vb 0 Sva -250 +2.5va +va - Vb = 0 8.5va-vb-250 = 0 8.5Va-Vb = 250 4CL node 1 2000 1000 200 л 400~ Na Va Va-vb = 0 + t 75V 100 400 500 node 2: Vb-Va 500 Vb Vb - 75-0 t 400 200 Vb-va + 1.25V b + 2.5 cub-75) Soo 500 500 CVb-va) +1.25 Vb + 2.5 (vb-73) = 0
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