CP CALC A 5.00-kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the end of the rope, and the height of the crate above its initial position is given by y(t) = (2.80 m/s)t + (0.610 m/s³)r³. What is the magnitude of the force F when t = 4.00 s? 5.24 горе %3D

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter5: Newton's Laws Of Motion
Section: Chapter Questions
Problem 23PQ: The x and y coordinates of a 4.00-kg particle moving in the xy plane under the influence of a net...
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5.24 • CP CALC A 5.00-kg crate is suspended from the end of a
short vertical rope of negligible mass. An upward force F(t) is
applied to the end of the rope, and the height of the crate above its
initial position is given by y(t) = (2.80 m/s)t + (0.610 m/s')t³.
What is the magnitude of the force F when t = 4.00 s?
%3D
Transcribed Image Text:5.24 • CP CALC A 5.00-kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the end of the rope, and the height of the crate above its initial position is given by y(t) = (2.80 m/s)t + (0.610 m/s')t³. What is the magnitude of the force F when t = 4.00 s? %3D
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