Consider a W14x43 (Fy = 100 ksi) used as a compression member in a truss with Lc = 5 ft. What is the design compression strength for this member about the weak axis?
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- A large precast concrete panel for a warehouse is raised using two sets of cables at two lift lines, as shown in the figure part a. Cable 1 has a length L1 = 22 Ft, cable 2 has a length L2= 10 ft, and the distance along the panel between lift points Band D is d = 14 ft (see figure part b). The total weight of the panel is W = 85 kips. Assuming the cable lift Forces F at each lift line are about equal, use the simplified model of one half of the panel in figure part b to perform your analysis for the lift position shown. Find the required cross-sectional area AC of the cable if its breaking stress is 91 ksi and a factor of safety of 4 with respect to failure is desired.Repeat Problem 11.3-9. Use two C 150 × 12.2 steel shapes and assume that E = 205 GPa and L = 6 m.A steel riser pipe hangs from a drill rig located offshore in deep water (see figure). (a) What is the greatest length (meters) it can have without breaking if the pipe is suspended in the air and the ultimate strength (or breaking strength) is 550 MPa? (b) If the same riser pipe hangs from a drill rig at sea, what is the greatest length? (Obtain the weight densities of steel and sea water from Table M, Appendix I. Neglect the effect of buoyant foam casings on the pipe.)
- -11 A rubber cube R of a side L = 3 in. and cross- sectional area A = 9 in2 is compressed inside a steel cube S by a force F = 5 lb that applies uniformly distributed pressure to the rubber. Assume E 0.3ksi and,, = 0.45. (a) Calculate the lateral pressure between the rubber and steel (disregard friction between the rubber and the steel, and assume that the steel block is rigid when compared to the rubber). (b) Calculate the change in volume of the rubber.Find the forces in CE and DE of the truss shown in Figure (6) below (indicate tension or compression). Assume all joints are pinned. "tan (2+5) = 56.3² H pe 0.67 B 1m 1m C 1KN 1m 1m 1m F Figure (6) FDE = 0.4 kN (C) & FCE = 0.67 kN (T) 10% bis -75 0.75m G PNG 6-3-1+NG 3 NG= mbination of the method of jointsA team of design engineers are designing an amusement park structure as in Figure 2below. The horizontal beam supporting the gondolas at both ends are supported by 2vertical bars, bar EB and bar CF with a cross sectional area of 11,100mm2 and 9,280mm2each. Gondola 1 (left) weighs 380 kN and Gondola 2 (right) weighs 360kN respectively. Due to theweight of both the gondolas, the design team needs to investigate the verticaldisplacements of both ends of the horizontal beam at A and D. You are required to helpthem analyze and calculate the vertical displacement at both ends due to the weight ofthe gondolas.
- using the method of sections , analyse the truss shown in figure 8 below reguarding forces in menbers ED , DF AND FC .PROBLEM: Determine the forces in each member using any methoddiscussed in your theory of structures/mechanics. Using Software is notallowed. Show complete solution and tabulate your answers indicatingwhether it is compression or tension. Use Pn = 205 kN, Po = Zero. a) From the Problem and the image , Design one tension member, use either a double angle of a wt section. Check its adequacy using 1 line of bolts (three bolts in a line spaced at 75mm on centers) Assume a bolt diameter from 16-22mm. Use A 36 for all steel. Neglect block shear.Fundamental Problem 6.5 - Enhanced - with Hints and Feedback Consider the truss shown in (Figure 1). Part A Identify the zero-force members in the truss. Check all that apply. • Vlew Available Hint(s) O AB O BC O BD O DE O AE O CD BE Figure < 1 of 1 Submit Previous Answers 3 kN X Incorrect; Try Again; 5 attempts remaining -2 m 2m You have checked at least one member that is not a zerc 1.5 m Provide Feedback
- For the below Truss, we need to calculate the reaction, the internal forces in the members and design the critical members. Take Fx- 45 kN, Fy 15 kN, L-6 m; Fy Fx, 45° Bar 1 Bar 2 45° B Bar 3 L (m) Materials properties : Steel, Young Modulus E-220 GPa. Yield Stress Ys = 210 MPa, Ultimate stress UTS = 400 MPa. Section type : Rectangular Hollow. Safety Factor F.S = 2 for tension, FS = 3 for compression Questions: L (m)8. Calculate for the cross-section of members AG, BC, and CE for the truss assembly shown in the figure below, considering that the stresses are not to exceed 20 ksi categorized in tension and 14 ksi categorized in compression. NOTE: A reduced stress in compression is specified to reduce the danger of buckling. Figure P-112 4 ft 3. 4 ft F 25 kips 4 ft 40 kips 6ftConsidering the effects of the prestressing forces (assume no loss) and the working loads (include the selfweight of the beam). Calculate the stress indicated below. Calculate ftop at midspan. (MPa), consider sign convention (- for compression, + for tension) 5 KN/m EXCLUD In6 SELFWEI6 HT 300 = P P=300 kN I5 M オ 400 8e = 24 IN m3 N.A. 800 70 主