Consider a different mutant allele in gene V (allele ID: v4). Interestingly, many (but * not all) heterozygotes (v4/+) do not even make one vulva (the vulva fails to develop). In other words, a significant percentage of v4/+ animals are vulvaless. Choose "True" for words that you can use to describe the v3 allele. Choose False for words you cannot use.
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- Each box represents a potential offspring. Notice that genotypically speaking, they are all the same. Theyare all heterozygous (genotype) which means their phenotype is dark coloration. So, there is 100% chanceof producing a dark eyed, heterozygous offspring. What if that offspring mated with a light eyedindividual? Can you make a Punnett Square for that?Write the Genotypes and Phenotypes of the parents on the left of the square. Complete the square, thenwrite the potential offspring’s genotypes and phenotypes on the right of the square. Parents: Offspring:Genotypes: phenotypes: What are the genotypes of the resulting offspring? What are the phenotypes of the resulting offspring?You have a female snail that coils to the right, but you do not knowits genotype. You may assume that right coiling (D) is dominant toleft coiling (d). You also have male snails of known genotype.How would you determine the genotype of this female snail? Inyour answer, describe your expected results depending on whetherthe female is DD, Dd, or dd.Chorionic villus sampling (CVS) is used to test for genetic disorders in the fetus and can be performed early in gestation (8-10 wks). The recommended method of CVS is to sert a probe with a needle on the end through the cervix and remove a small sample of e chorionic villi to be analyzed. Which description is a correct description of chorionic villi? Select one: They are found in the digestive tract of the fetus. They are developed from the endometrium. They contain cells whose nuclei differ genetically from cells of the fetus. They form part of the placenta.
- You are an allele on a single uncondensed chromosome in a Yellowfever-carrying mosquito (Aedes aegypti) diploid cell (2n = 6). Demonstrate in as much detail as possible (1) how you will get to each genetically identical diploid cell of the multicellular offspring; (2) how you will get to the next generation of sexually reproduced progeny. Help, I no understand. Perhaps you will?"In the small intestine, stem cells in the crypts divide asymmetrically to maintain the population of cells that make up the villi; after each division, one daughter remains a stem cell and the other begins to divide rapidly to produce differentiated progeny" is true or false.Spherocytosis is an inherited blood disease in whichthe erythrocytes (red blood cells) are spherical insteadof biconcave. This condition can be inherited in adominant fashion, with ANK1 (the nonfunctional mutant allele) dominant to ANK1+. In people with spherocytosis, the spleen recognizes the spherical redblood cells as defective and removes them from thebloodstream, leading to anemia. The spleen in different people removes the spherical erythrocytes withdifferent efficiencies. Some people with sphericalerythrocytes suffer severe anemia and some mild anemia, yet others have spleens that function so poorly nosymptoms of anemia exist at all. When 2400 peoplewith the genotype ANK1 ANK1+ were examined, itwas found that all of them had spherical erythrocytes,2250 had anemia of varying severity, and 150 had nosymptoms. (Assume that ANK1 ANK1 homozygotesdo not exist.)a. Does this description of people with spherocytosisrepresent incomplete penetrance, variable expressivity, or both? Explain…
- Aristapedia is alethal allele that is also dominant. Individuals with this trait must be heterozygous (Aa) because the homozygous condition (AA) is lethal. Wild type alleles do not carry the allele for aristapedia (aa). Predict what the outcome of a cross between a male and a female fly which both carry the aristapedia allele by showing a diagram. Then, go to FlyLab JS virtual lab and simulate the cross. Determine if the observed offspring is fit to the ratio that you obtained from your cross.(Use whole number only)Consider a Droscophilia fly with a genotype of Nn XqYY. The dominant allele of the sex-linked gene specifies a black body and the recessive a white body. The recessive autosomal allele specifies hairy bristles while the dominant allele specifies smooth bristles. i)What is the ploidy of this fly? ii) What would the sex of this fly be? iii)What would the phenotype of this fly be with respect to these two loci?Let’s suppose that you have made a karyotype of a female fruit flywith red eyes and found that it has three X chromosomes insteadof the normal two. Although you do not know its parents, you doknow that this fly came from a mixed culture of flies in whichsome had red eyes, some had white eyes, and some had eosin eyes.Eosin is an allele of the same gene that has white and red alleles.Eosin is a pale orange color. The red allele is dominant and thewhite allele is recessive. The expression of the eosin allele, however, depends on the number of copies of the allele. When femaleshave two copies of this allele, they have eosin eyes. When femalesare heterozygous for the eosin allele and the white allele, they havelight-eosin eyes. When females are heterozygous for the red alleleand the eosin allele, they have red eyes. Males that have a singlecopy of the eosin allele have eosin eyes.You cross the XXX red-eyed female with a white-eyed male andcount the numbers of offspring. You may assume that…
- Termites have a haplo-diploid sex determination system where females develop from a fertilized egg (they are diploid, having one allele from the female cueen and one allele from the male), and males develop from unfertilized eggs (they are haploid, having only one allele from the queen). Assuming that the female parent (queen) is heterozygous for a particular gene, what is the probability that a female offspring will inherit the recessive allele from her mother? What is the probability that a male offspring will inherit a recessive allele from his mother? O A. The probability that a daughter will inherit a recessive allele from her mother is 50%; the probability that a son will inherit a recessive allele from his mather is 50%. OB. Ihe probobility that a daughter will inherit a recessive allele from her mother is 0%; the probability that a son will inherit a recessive allele from his mother is 100%. O C. The probability that a daughter will inherit a recessive allele from her mother is…What is the correct table in these two given? 1. Take two coins and assume that heads represent the dominantallele (A) and tails represents the recessive allele (a). The genotype for each coin isheterozygous (Aa).2. Assume that each coin represents one parent. When a single coin is flipped, one gameteis formed (through the process of meiosis). If the flipped coin is on heads, then thegamete has the dominant allele (A). When both coins are flipped simultaneously, therewill be two possible gametes that can combine through fertilization to form a zygote. Eachtime you flip both coins, you will record the “genotype” of the offspring.3. Flip the coins 100 times and record your results in the chart belowThe XG locus on the human X chromosome has twoalleles, XG+ and XG. The XG+ allele causes the presence of the Xg surface antigen on red blood cells,while the recessive XG allele does not allow antigento appear. The XG locus is 10 m.u. from the STSlocus. The STS+ allele produces normal activity ofthe enzyme steroid sulfatase, while the recessive STSallele results in the lack of steroid sulfatase activityand the disease ichthyosis (scaly skin). A man withichthyosis and no Xg antigen has a normal daughterwith Xg antigen. This daughter is expecting a child.a. If the child is a son, what is the probability he willlack Xg antigen and have ichthyosis?b. What is the probability that a son would have boththe antigen and ichthyosis?c. If the child is a son with ichthyosis, what is theprobability he will have Xg antigen?