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- Q2) A 13.2-kV single-phase generator supplies power to a load through a transmission line. The load's impedance is Ztoad 500 236.87° ohm , and the transmission line's impedance is Zine = 60 253.1° ohm. To reduce transmission line losses to 0.0103 of its losses without using the transformers design and use two transformers T1 between the generator and the transmission line and T2 between the transmission line and the load.A parallel connection of a RL branch with a C branch is connected across a 100V AC mains. At first R = 10 ohms, L = 20mH and frequency of 1000rad / s, the current measured is 2.2361A at 89.44 leading power factor. A) Determine the initial capacitance. B) However, a fault occurs on the capacitor branch making its capacitance 20% lower and a resistance of 5 ohms is detected. If this faulty circuit is rerun but at a frequency of 500 rad / s, determine the new current that will flow through the circuit.A synchronous generator has been synchronized to an infinite grid of 13.8 kV and 60 Hz. The generator prime mover C/C is such that the no-load frequency is 62.5 Hz and the power slope is 1 MW/Hz. The AVR C/C (The reactive power against the terminal voltage C/C) is such that the zero reactive power voltage is 14.6 kV, while the slope is 0.4 MVAR/kV. Calculate (a) the kVA loading of the generator and its power factor. (b) the settings of the prime mover and AVR such that the generator delivers 3 MW at 0.85 lagging power factor.
- A 480V/240V, 60Hz single transformer has Z1 = 0.1+j0.22 ohms and Z2 = 0.035 + j0.12 ohm. Find the equivalent impedance in ohm referred to the secondary. Group of answer choices 0.07+j0.135 0.06+j0.175 0.04+j0.135 0.06+j0.1355.5 kW, 1450 rpm. L-type equivalent circuit and parameters for a continuous sinusoidal phase of a star connected 3-phase ASM with line voltage 220 V and frequency 50 Hz are given as follows, ignoring core (iron) losses: R1=0.21 Ohm, R2=-0.18 Ohm, X1=X2-0.66 Ohm and Xm = 9.9 Ohm How many times the inrush current will be the rated current when the ASM is started directly? Answer options group 8.0815 2.6455 4.3763 7.1534 1.2558 6.3414 5.2280 3.7473A- A 3-ph, double circuit O.H.T.L, 320 kV, 340 km, 50 Hz has a configuration as shown in the figure below where each phase in the double circuit has a double bundle with a spacing of d cm between the two conductors in the bundle where d is the last two digits (from right) of your registration number (i.e for the student that has a registration mumber 202112396, d= 96). Each conductor in the bundle has a diameter of 0.135 ft and a geometric mean radius (Ds = 1.6 cm). Calculate: 1- Inductance per phase per km. 2- Total inductive reactance. 3- This T.L. is required to supply 240 MVA at 0.86 lag P.f. at 320 kV, assuming that this load is divided equally between these two circuits, find the voltage drop across this T.L (ignore capacitive effect in the calculation). 4- What may happen if we replace the location of a' and c' bundles. Discuss your answer. 5- Suggest a way to ređuce the value of the inductance. Verify your suggestion. -8 m 3m 3m 8 m 11 m
- L-type equivalent circuit and parameters for a continuous sinusoidal phase of a 5.5 kW, 1480 rpm, line voltage 220 V and frequency 50 Hz star-connected 3-phase ASM, ignoring core (iron) losses given as follows: R1=0.21 Ohm, R2=0.18 Ohm, X1=X2=0.66 Ohm and Xm=9.9 Ohm i, i, R, R, eee R, (1-s) m S How many times the rated current will the inrush current be when the ASM is started directly? O 6.3414 O 1.2558 5.2280 O 3.7473 O 7.1534 4.3763 O 2.6455 8.0815Two power system areas operating at a nominal frequency of 60 Hz are connected with a tie line, and have the following characteristics: Area 1: R1 = 0.02 pu and D1 = 1 pu on a base of 1200 MVA Area 2: R2 = 0.03 pu and D2 = 0.8 pu on a base of 700 MVA The power flow direction on the tie line is from Area 1 to Area 2. Using a common base of 1000 MVA, what is the change in tie flow (in MW) for a load increase of 200 MW in Area 1? Select one: a.-56.16 MW O b. None of these O c.-143.84 MW O d.-38.02 MW <6.5% ans ex A so kvA. 2o00/20 V, So He single-phase transformar has impedance drof of8% and resistance drop of 4%. Caleulate. The Requlation of the Thams former at full- Load o8 P.s Legging. also find The Power factor at which Voltage requlation will Be Zero. Sols 0.5 leading. s alculate The % Noltege Requlation af atransformar in w hich the Percantage resistance drof is 1% and Percentage dre is 6% when The Power fador is 0.8 lagging ) > unity aMS 38 % ans 1 % (シ→ 0.8 leading . amS - 2.2%
- Problem 5 Consider a three winding transformer with the following particulars: = Z₁ Z2 Z3 =0.02 + j0.08 £, V₂ = 400 V, 12 = 60/30° A, and I3 = 50/-40° A. Assume that V₂ is the reference phasor, calculate: The intermediate voltage Vo. a. b. The primary current I₁ and the primary voltage V₁. c. The tertiary voltage V3 referred to the primary side. d. The apparent powers and the power factors at the primary, secondary and tertiary terminals. e. The transformer efficiency.Q.3 Power Systems - Basics of Power Syst... A power system is represented by a single line diagram which is shown below p.u do 11 12 The Ratings of the system is as follows Generator rating = 40 MVA, 25 KV, XG = 0.2 hee Transformer T₁ Rating = 33/220 KV. What will be the p.u reactance of generator near to transformer 1 to a base of 100 MVA, 33KV?2) The one-line diagram of a three-phase power system is as shown in Figure. Impedance are marked in per-unit on a 100-MVA, 400-kV base. The load at bus 2 is S2=15.93 MW - j33.4 Mvar, and at bus 3 is S3-77 MW + j14 Mvar. It is required to hold the voltage at bus 3 at ...L0 kV. Working in per-unit, determine the voltage at buses 2 and 1. (Please determine the voltage magnitude within the specified limits: 410-450 V. By considering the voltage magnitude value you determined yourself, solve the question.) V₁ j0.5 pu V₂ j0.4 pu S₂ Figure V3 S3