an initially stationary block of mass m on a floor. A force of magnitude 0.500mg is then applied at upward angle u=20.What is the magnitude of the acceleration of the block across the floor if the friction coefficients are (a) ms = 0.600 and mk = 0.500 and (b) ms =0.400 and mk = 0.300?

an initially stationary block of mass m on a floor. A force of magnitude 0.500mg is then applied at upward angle u=20.What is the magnitude of the acceleration of the block across the floor if the friction coefficients are (a) ms = 0.600 and mk = 0.500 and (b) ms =0.400 and mk = 0.300?

Name: an initially stationary block of mass m on a floor. A force of magnitu
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: an initially stationary block of mass m on a floor. A force of magnitude 0.500mg is then applied at upward angle u=20.What is the magnitude of the acceleration of the block across the floor if the friction coefficients are (a) ms = 0.600 and mk = 0.5

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter5: Newton's Laws Of Motion

Section: Chapter Questions

Problem 32PQ: If the vector components of the position of a particle moving in the xy plane as a function of time...

See similar textbooks

Similar questions

The x and y coordinates of a 4.00-kg particle moving in the xy plane under the influence of a net force F are given by x = t4 6t and y = 4t2 + 1, with x and y in meters and t in seconds. What is the magnitude of the force F at t = 4.00 s?
A crate with a mass of m=254kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate and the deck is μs=0.83. The coefficient of kinetic friction is μk=0.47. Write an expression for the magnitude of the force, Fv, that must be applied to keep the block moving at a constant velocity.
A block of mass 8.3 kg is initially at rest on a horizontal plane. The coefficients of kinetic and static friction between the plane and the block are respectivelyμc= 0.25 and μe= 0.36. Consider g = 10 m/s2 A horizontal force of magnitude F = 26.3 N is then applied to the block. In this situation, calculate the magnitude of the friction force (in N, to one decimal place).
The figure below shows an initially stationary block of mass m on a floor. A force of magnitude F = 0.490mg is then applied at upward angle 0 = 23°. (a) What is the magnitude of the acceleration of the block across the floor if the friction coefficients are us = 0.595 and uy = 0.490? m/s2 (b) What is the magnitude of the acceleration of the block across the floor if the friction coefficients are us = 0.395 and uy = 0.305? m/s2 Additional Materials
A crate with a mass of m=254kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate and the deck is μs=0.83. The coefficient of kinetic friction is μk=0.47. Write an expression for the magnitude of the minimum force, Fmin that must be applied to get the block moving from rest.
You are pushing a metal crate against a metal floor. The two surfaces have a static coefficient of friction of 0.62 and a kinetic coefficient of friction of 0.50. The floor is horizontal, and the crate has a mass of 25.0 kg. What is the minimum force you need to apply to get the crate moving from rest? Give your answer in units of N, to three significant figures.
A wedge with mass M rests on a frictionless m horizontal tabletop. A block with mass m is placed on the wedge and a horizontal F force F is applied to the wedge. There M is no friction between the block and the wedge. For a = "/7, what must the magnitude of F be if the block is to remain at a constant height above the tabletop? (g is the magnitude of the gravitational acceleration. Take m = 1 kg, M = 5 kg and g = 10 m/s².) %3D (a) 29 N (b) 35 N (c) 44 N (d) 60 N (e) 104 N
A block of mass m1 = 3.9 kg is placed on top of a block with mass m2 = 5.4 kg. A force, F = is applied to m2, at an angle 16.1 degrees above the horizontal. If the coefficient of static friction between all moving surfaces is 0.42 and the coefficient of kinetic friction is 0.32, determine the magnitude of the minimum force that will get the blocks moving.
A block of mass 20kg is pushed against a vertical wall by force P. The coefficient of friction between the surface and the block is 0.2. If theta = 30 degrees, what is the minimum magnitude of P to hold the block still?I understand that in order for the block to sit motionless, the net forces acting on the block must be zero. I set my equation to be Net Force = 0 = Psin(theta) + Force Friction - Force Gravity.Which I rearranged as P = (Force Gravity - Force Friction)/sin(theta) or P = (mg-μ(mg))/sin(theta)Doing this gives me a value of 313.6N rather than 202.9N which I should be getting. What am I doing wrong?
A 12 N horizontal force pushes a block weighing 5.0 N against a vertical wall . The coefficient of static friction between the wall and the block is 0.60, and the coefficient of kinetic friction is 0.40. Assume that the block is not moving initially. (a) Will the block move? (b) In unit-vector notation, what is the force on the block from the wall?
A block of mass m =1 kg, slides down a rough incline with constant velocity. The coefficient of kinetic friction between the block and the incline is µr, and the incline makes an angle 0 = 30° horizontal. Take g = 10 m/s2. The coefficient of kinetic friction µ is then equal to: v= constant with the O 0.577 O 0.466 O 0.422 O 0.364
The figure below shows an initially stationary block of mass m on a floor. A force of magnitude F = 0.510mg is then applied at upward angle 0 = 19°. (a) What is the magnitude of the acceleration of the block across the floor if the friction coefficients are us = 0.590 and uk = 0.505? m/s? (b) What is the magnitude of the acceleration of the block across the floor if the friction coefficients are ug = 0.395 and uk = 0.295? m/s2