Ammonium nitrate has been used as a high explosive because it is unstable and decomposes into several gaseous substances. The rapid expansion of the gaseous substances produces the explosive force. NH4NO3(s) → N2(g) + O2(g) + H2O(g) Calculate the mass of each product gas if 1.29 g of ammonium nitrate reacts. N2   g O2   g H2O   g

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Chapter9: Chemical Quantities
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Ammonium nitrate has been used as a high explosive because it is unstable and decomposes into several gaseous substances. The rapid expansion of the gaseous substances produces the explosive force.

NH4NO3(s) → N2(g) + O2(g) + H2O(g)

Calculate the mass of each product gas if 1.29 g of ammonium nitrate reacts.

N2   g
O2   g
H2O   g
Expert Solution
Given

NH4NO3(s) → N2(g) + O2(g) + H2O(g)

Mass of ammonium nitrate = 1.29 g

 

To calculate the mass of product in the reaction , first convert this mass of reactant to moles .

From this moles of reactant , Calculate the moles of product formed.

At the end convert this Moles to mass , to get final answer

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