A Single Edge Bend sample is tested to determine the fracture toughness of a material. The sample setup is shown in the figure below: Some important information on the test is given in the table below. The shape factor has been calculated for you. From the information provided, determine an interim value for Fracture Toughness in MNm 3/2, Give your answer to one decimal place. Enter your answer without units. Load at Failure Load at 95% Linear Gradient L W F Į Sample Width (B) Shape Factor L 44.7 KN 29.2 KN 161 mm 63 mm 35 mm 2.238 B W

A Single Edge Bend sample is tested to determine the fracture toughness of a material. The sample setup is shown in the figure below: Some important information on the test is given in the table below. The shape factor has been calculated for you. From the information provided, determine an interim value for Fracture Toughness in MNm 3/2, Give your answer to one decimal place. Enter your answer without units. Load at Failure Load at 95% Linear Gradient L W F Į Sample Width (B) Shape Factor L 44.7 KN 29.2 KN 161 mm 63 mm 35 mm 2.238 B W

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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640 480 160 0.002 0,004 0.006 0.008 0.010 Strain (mm/mm) A tensile test specimen of Aluminum alloy having a gauge length of 280 mm was tested to fracture. Stress and strain data obtained during the test are shown in the attached Figure. **Answers are approximate - do your best to read the graph. Determine: (a) the modulus of elasticity in GPa (4sigs). Enter this value into D2L answer box. (b) the proportional limit in MPa (3sigs). (c) the ultimate strength in MPa (3sigs). (d) Ductility of material based on percent elongation. (3sigs) Your Answer: Stress (MPa)
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The table below shows the deformation data that resulted from applying a pure tensile load to a brass alloy rod with an initial length of 30 mm and a diameter of 10 mm. This rod was subjected to necking and beyond necking deformation. The data at fracture is shown in the last row. Applied Load (N) Length (mm) Diameter (mm) 75,100 33.8 68, 250 34.9 50,200 35.7 6.7 Solve for the TRUE STRESS/ES and TRUE STRAINS. 8.3 7.8
a . Sketch stress strain curve if the result shown in table represent the force and extension happened in steel, and show Mechanical properties that we get from tensile test on curve? (10p)Note : Lo=80 mm , Do=10 mm , use excel to plot the curve ExtensionLoad(mm) (N)0 0.900.83 4694.341.67 4831.412.50 4781.083.33 4918.834.17 4926.585.00 5257.075.83 5437.016.66 5575.888.33 5775.189.16 5847.5210.83 5965.4111.67 6010.5312.50 6042.5713.33 6072.2614.16 6092.9315.00 6113.2416.67 6140.3617.50 6146.3718.33 6148.1419.16 6149.1725.00 5940.2125.83 5675.3326.67 4725.52b. What is meant by modulus of rigidity? if it increases what does happen to material? (2p)
1. Plot the engineering stress & strain diagram of an alloy having a tensile test result found in Table 1. The tensile test specimen has a diameter of 12.5mm and a gage length of 50.0mm. The given alloy is used to make a 30.0mm diameter cylinder, which is placed inside a hardened circular steel casement with a 30.01mm inner diameter. Table 1: Tensile test results of an alloy Change In Length (mm) Change In Diameter (mm) Load (kN) 0.000 0.0000 0.0000 4.364 0.0254 -0.0019 13.092 0.0762 -0.0057 21.819 0.1270 -0.0095 30.547 0.1778 32.729 0.7620 34.911 3.0480 30.01 mm Ø F Rigid Plate Cylindrical Alloy - Steel casement Figure 1: Section view of the steel casement encapsulating the cylindrical alloy 2. Determine the required minimum value of F such that the cylindrical alloy would touch the walls of the steel casement.
1. Plot the engineering stress & strain diagram of an alloy having a tensile test result found in Table 1. The tensile test specimen has a diameter of 12.5mm and a gage length of 50.0mm. The given alloy is used to make a 30.0mm diameter cylinder, which is placed inside a hardened circular steel casement with a 30.01mm inner diameter. Table 1: Tensile test results of an alloy Change In Length (mm) Change In Diameter (mm) Load (kN) 0.000 0.0000 0.0000 4.364 0.0254 0.0019 -0.0057 13.092 0.0762 21.819 0.1270 0.0095 30.547 32.729 0.1778 0.7620 34.911 3.0480 30.01 mm O F Rigid Plate Cylindrical Alloy -Steel casement Figure k Section view of the steel casement encapsulating the cylindrical alloy 2. Determine the required minimum value of F such that the cylindrical alloy would touch the walls of the steel casement.
The following curve is a result of a tensile test. The gauge length was 2 in, and the specimen diameter was 0.505 in The fracture area was round with a diameter of 0.391 in. Remember to com 20000 Force (pounds force) 15000 10000 5000 0 16. The yield strength is 0 0.2% O 80,000 pl O 12.000 p 060,000 pl 85,000 p 0.1 0.2 Extension (inch) 0.3 0.4
Question A cylindrical specimen of metal having a diameter of 12.88 mm and a gauge length of 63.50 mm is tested using a tensile testing machine. The elongation measurement are recorded in Table 3. nPlot the stress-strain curve on the graph paper provided based on data in Table 3 Based on the stress-strain curved plotted in (i): Compute the modulus of elasticity Determine the yield strength at a strain offset of 0.002. Determine the tensile strength Determine the ductility in percent elongation and percent area reduction Table 3: Load-elongation readings for a metal specimen Jadual 3: Bacaan beban pemanjangan untuk statu spesimen logam) Load (N) Elongation (mm) 1380 0.03 2780 0.06 5630 0.12 7430 0.2 8140 0.25 9870 0.64 12850 1.91 14100 3.18 14340 4.45 13830 5.72 12500 6.99 Fracture
Ql- mm ,length 40 mm. The final diameter 18 mm and length 45 mm. Draw the force-extension diagram and determine the following : a) Ultimate tensile strength, c) Modulus of elasticity, d) Percent elongation and e) Percent reduction in area. The following data collected from tensile test of a metal bar diameter 20 b) The fracture strength, Force - kN 75 90 | 105 120 131 125 110 25 50 4.7 Extension-mm 0.02 0.04 0.06 0.20 - 0.60 1.60 3.00 4.0 Fracture
Given the following stress-strain graph:a. is the modulus of elasticity of "A-514" greater, less or equal to the one of "A-572"?b. from the previous question, make an estimatio for both of them, check that the graphic comes in %c. If we were to test these materials in a universal tension equipment, which one would withstand more load?d. If we were to test these materials in a universal tension machine, which one would elongate the most before fracturing? would elongate the most before fracturing? e. Of the 6 materials shown, do any behave as brittle materials? f.
5. The following data were collected from a standard 0.505-in.-diameter test specimen of a copper alloy (initial length lo= 2.0 in.). After fracture, the total length was 3.014 in. and the diameter was 0.374 in. Load (Ib) Al (in.) 00000 3,000 6,000 0.00167 0.00333 7,500 0.00417 9,000 10,500 0.0090 0.040 12,000 0.26 12,400 11,400 0.50 (maximum load) 1.02 (fracture) a) Plot the data as engineering stress versus engineering strain. b) Compute the modulus of elasticity. c) Determine the yield strength at a strain offset of 0.002. d) Determine the tensile strength of this alloy. e) What is the approximate ductility, in percent elongation? f) Compute the modulus of resilience. g) Compute from the data and plot true stress versus true strain diagram.
1. A bronze alloy specimen having a diameter of 12.8 mm and a gage length of 50 mm was tested to fracture. Stress and strain data obtained during the test are shown in Figure. Determine: 400 Upper scale a. the modulus of elasticity. b. the proportional limit. c. the ultimate strength. 320 Lower scale 240- d. the yield strength (0.20% offset). 160 e. the modulus of resilience. f. the true fracture stress if the 80 final diameter of the specimen at the location of the fracture was 10.5 mm. 0.100 0.200 0.300 0.400 0.005 0.010 0.015 0.020 g. The Poisson's ratio. Strain (mm/mm) Stress (MPa)