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A force F of magnitude 665 N lies in the line of action AB = 3i - 1j + 1.6k. What is the magnitude of the y-component of the force?
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- Vector B has x, y, and z components of 4.00, 6.00, and 3.00 units, respectively. Calculate (a) the magnitude of B and (b) the angle that B makes with each coordinate axis.The rocket engine on a test stand exerts an upward force of 36 MN vertically upward. If you resolve the force into vector components parallel to the bars AB and CD, what are the magnitudes of the components? Given that the angle θθ is 42 degree.Two forces are applied to an object, F1=3i-2j , F2=i+3j . What is the resultant force on the object? Calculate the magnitude of the resultant force and the angle it makes with the x axis.
- A force F1 of magnitude 5.20 units acts on an object at the origin in a direction theta = 48.0 above the positive x-axis. A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find the graphically the magnitude and direction of the resultant force F1+ F2.Problem 5. A force F of magnitude 6.00 units acts on an object at the origin in a direction u 30.0 degrees above the positive x axis. A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y axis. Find the magnitude and direction of the resultant F + F2.a force F1=315N acts in the first quadrant at an angle of 70 degress above the x axis, while a second force F2=210N acts in the third quadrant at an angle of 40 degrees below the x axis. What is the magnitude of the resultant of these two forces. What is the direction (theta) of the resultant ?
- A horizontal line PQRS is 12 m long, where PQ = QR = RS = 4 m. Forces of 1000 N, 1500 N, 1000 N and 500 N act at P, Q, R and S respectively with downward direction. The lines of action of these forces make angles of 90°, 60°, 45° and 30° respectively with PS. Find the magnitude, direction, and position of the resultant force.In the figure below, a force F, of magnitude 5.50 units acts on an object at the origin in a direction 0 = 32.0° above the positive 1 x-axis. A second force F, of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the 12 magnitude and direction (in degrees counterclockwise from the +x-axis) of the resultant force F, + F,. 2: magnitude units direction ° counterclockwise from the +x-axis 2,Three force vectors act on a free body at the origin as shown. F1= 4 N F2=2.0 i + 3.1 J N F3= 6.3 N at 35° relative to positive x axis. a) Report the unit vector in the direction of F3 (in unit vector or i,j,k notation to 4 sig figs) b)Calculate the resultant force R, which is the sum of the three forces F1,F2, and F3 (in unit vector or i,j,k notation to 4 sig figs)
- P = 244 N and the couple M = 635 Nm Magnitude of resultant force =104.9 N Determine the angle (in degrees) that the resultant makes with the positive x-axis, which is in the same direction as the horizontal force P.Two individuals are attempting to relocate a sofa by applying forces in the indicated directions. If F₁ = 490 N and F2 = 400 N, determine the vector expression for the resultant R of the two forces. Then determine the magnitude R of the resultant and the angle which it makes with the positive x-axis (measured counterclockwise from the x-axis). I F2 69⁰ -1 F₁ Answers: R= j) N R = e= i B i+ i NThe forces acting on the sailplane are its weight W = -500j (lb.) , the drag D = -200i + 100j (lb.), and the lift L. The sum of the forces W + L + D = 0. Determine the composnents and the magnitude of L.
