A box is suspended by 3 cables as shown. If the weight of the box, W = 571b, cable C has coordinate angles, a = 103°, 118°, y=46° and cable A has a unit vector Ua =-0.576i +0.429j. What is the tension in cable B? A a Y Z B
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- What are the tensions in each of the 4 cables supporting the lamp, if the lamp weighs 40 Ibs and the coordinate direction angles for Cable B are a = 95°, ß = 140° and y = 50.44°? Cable B Cable A 30° 50 Cable C 1 ft 3 ft Cable D 4 Using the figure from Question 3, determine the maximum weight of the lamp if no cable can support more than 75 Ibs of tension? You can reuse the Cartesian force vector expressions for TA, TB and Tc from Question 3 i.e. you do not need to derive them again for this question.Find the tension in each of the 3 strings in each of the two diagrams in terms of w (something times w or w over something). (a) a = 29° B = 44° (a) B A (b) XC a = 59° B = 44° (b) B. a B.Q2/ The cable BC carries a tension of 750 N. Write this tension as a force T acting on point B in terms of the unit vectors i, j, and k. The elbow at A forms a right angle. Ans. T= -598i + 41lj +189.5 k N 12m- 1.6 m 0.7 m A. 30 0.8 m B
- Be careful, you have only one question, for this problem. The pulling force is P = 545N. The direction of the rope B is defined by the angle 0-35deg. The position of the point D is (1.3,-2.3.3.1) Xo D Zo Y X P What is the tension Tc in N? Give your answer as an integer. o B -yQ2/ The cable BC carries a tension of 750 N. Write this tension as a force T acting on point B in terms of the unit vectors i, j, and k. The elbow at A forms a right angle. Ans. T = -518i + 41lj + 189.5 k 12m C 1.6 m 0.7 m 30° 0.8 mE1.2 960 mm -1100 mm- 400 mm, B What is the largest mass the cables can support if the maximum allowable tension in AC or AB is 750 N? What is the unit vector pointing from C to B?
- 1. A 5kN force is applied to the pulley system as shown. The member OA is a simple two force member. Find the tensions that result in the two cables AD and AC. Show these tension forces in Cartesian notation. A T=5kN 6 m 2 m В y D 3 m 2 m 8 ma) What are the tensions in each of the 4 cables supporting the lamp, if the lamp weighs 40 Ibs and the coordinate direction angles for Cable B are a = 95°, ß = 140° and y = 50.44°? Cable B Cable A 30 50 Cable C 3 ft Cable D b) Using the figure above, determine the maximum weight of the lamp if no cable can support more than 75 Ibs of tension? You can reuse the Cartesian force vector expressions for TA, TB And TC From part a. you do not need to derive them again for this part.Applications Problem 1: A cart is pulled uniformly along two cables using two horses as shown below, the tension forces along the two cables are P 900 N and Q = 1100 N and the angle between them are a = 60°. Determine the magnitude of the resultant force (R)and the angles between the resultant and the two tension forces. Q = 1100N %3D a = 60° R=? Cart P = 900N %3D lution:
- A box is suspended by 3 cables as shown. If the weight of the box, W = 83 lb, and cable C has a unit vector, Uc= -0.500 i +-0.766 j+ 0.407 k and cable A has a unit vector Ua= -0.857 i+0.515 j. What is the tension in cable B? B4) Determine the total moment caused by the forces Fp4 and Fca about the plate diagonal that goes through point B (the dashed line). Write your answer in cartesian vector notation. FCA= 500 lb 14 ft FRA = 350 Ib FDA= 400 lb 3 ft-> 3 ft 3 ft 2 t 6 ftFind the sum of the horizontal forces in Newton if F1 = 100 N at 30 deg N of E and F2 = 80 N at 45 deg N of W.