#7, (a) Show lim (x+1)y does not exist. (x+1)²=42 that (x,y) + (-1,0) x+y²+1 (b) Given p(x, y, z) = ex²-4 + z ln (1+ y²) -1/2 where yzz x=u²=uv+~~ | y=W+v² 5, z=w²+V-u use the chain rule to find op (in terms ού x, y, z, u, v, w (C) Evaluate of when (u,v, w) = (1,2,0).

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.3: Maxima And Minima
Problem 20E
Question
#7, (a) Show lim
(x+1)y does not exist.
(x+1)²=42
that (x,y) + (-1,0) x+y²+1
(b) Given p(x, y, z) = ex²-4 + z ln (1+ y²) -1/2 where
yzz
x=u²=uv+~~ | y=W+v² 5, z=w²+V-u use
the chain rule to find op (in terms
ού x, y, z, u, v, w
(C) Evaluate of when (u,v, w) = (1,2,0).
Transcribed Image Text:#7, (a) Show lim (x+1)y does not exist. (x+1)²=42 that (x,y) + (-1,0) x+y²+1 (b) Given p(x, y, z) = ex²-4 + z ln (1+ y²) -1/2 where yzz x=u²=uv+~~ | y=W+v² 5, z=w²+V-u use the chain rule to find op (in terms ού x, y, z, u, v, w (C) Evaluate of when (u,v, w) = (1,2,0).
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