4.4.If an industrial plant is generating wastewater containing 350 mg/L of lysine [HO₂ CCH (NH2) (CH2)4NH2], the C-ThOD required is around:a) 538 mg 02/L b) 759 mg 02/Lc) 642 mg 02/Ld) 862 mg O₂/L4.5.A circular clarifier has a diameter of 60 ft. If the primary effluent flow is 2 MGD, what is the surfaceoverflow rate in gpd/ft²?a) 1080 gpd/ft²b) 708 gpd/ft²c) 845 gpd/ft²d) 777 gpd/ft²4.6.A stream with a velocity of 0.5 m/s, de-oxygenating rate of 0.2/day, and re-oxygenation rate of0.3/day. The ultimate BOD in the discharge point is 30 mg/L. The stream is in a saturation levelbefore outfall with a temperature of 20°C. Assume same temperature, what is the DO in 5 kmd) 12.3 mg/Ldownstream? a) 8.4 mg/Lb) 9.1 mg/Lc) 10.2 mg/L

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Answered: 4.4.If an industrial plant is…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Chemistry A sewage treatment plant discharges 4 ML/d of effluent with 20.17 mg/L BOD5 into a stream. The stream discharge is 12 ML/d, and its initial BOD5 is 6.10 mg/L. The initial DO of the wastewater is 2.10 mg/L and in the stream, it is 7.91 mg/L. Assume the stream velocity is 0.31 m/s and the dissolved oxygen saturation concentration is 8.76 mg/L. The kd = 0.15 d-1 and kr = 0.31 d-1 values have been adjusted for temperature. Calculate the minimum DO in the stream and determine the distance (km) downstream that this minimum occurs. Is this a safe level for fish?
A wastewater with a BOD of 25mg/L is discharged through an outfall to a freshwater stream of mean velocity 0.1m/s. The DO downstream of the outfall is 8.5mg/L. Assume the deoxygenation rate is 0.25/d, the reaeration rate is 0.4 /d and the temperature of 20 degree C (DOs = 9.09mg/L). Compute for the ff: a) Critical distance b) minimum DO c) Oxygen deficit d) Critical time
A municipal wastewater treatment plant processes an average of 14,000 m3 / day. The peak flow is 1.75 times the average. The wastewater contains 190mg/L BOD and 210 mg/L suspended solids at an average flow and 225 mg/L BOD and 365 mg/L suspended solids at peak flow. Determine the following for a primary clarifier with a 20-m diameter. Assume eff. BOD of 20 mg/L and effluent TSS of 30mg/L for average and peak flows. 1. Surface overflow rate and the approximate removal efficiency for BOD 5 and suspended solids @ average flow. 2. Surface overflow rate and the approximate removal efficiency for BOD 5 and suspended solids @ peak flow. 3. Mass of solids (kg/day) that is removed as sludge from average and peak flow conditions.
The wastewater from a manufacturing treatment plant is discharged to a municipal 'treatment plant for processing with domestic wastewater. The characteristics of the wastewater from the manufacturing treatment plant are 3500 mg/l BOD, 4500 mg/l SS, 70 mg/l nitrogen and 2 mg/l phosphorous. The characteristics of the domestic wastewater are 350 mg/I BOD, 285 mg/I SS, 50 mg/lN and 11 mg/I P. If the required BOD/N/P weight ratio is 100/5/1, what is the minimum quantity of domestic wastewater required per 1000 gallons of manufacturing wastewater to provide adequate nutrients for biological treatment and the concentration of SS in the combined wastewater?
A 14 mgd wastewater treatment plant has a primary clarifier that treats an influent with 800 mg/L of solids and a removal efficiency of 55%. Sludge at the bottom of the tank is pumped at a rate of 0.1 mgd. 1. What is the effluent solids concentration from the clarifier (in mg/L)? What is the solids concentration in the sludge at the bottom of the tank (in mg/L and %)? The primary sludge is further processed in a digester following treatment. What weight of solids (in lbs) need to be handled each week? а. b. с.
The PEF, Inc. firm desires to utilize a complete-mix activated-sludge system with recycle to treat their municipal wastewater after primary sedimentation. The design parameters are: Flow rate=0.92m³/s Influent Soluble BOD5 = 292mg/L MLVSS=2,500mg/L Mean cell residence time = 7.24 d For any missing parameters, use typical values of growth constants for domestic wastewater (provided in your text, page 494). Assume that the solids lost in the secondary clarifier effluent are minor and can be neglected. Assuming a BODs (S) concentration of 24 mg/L, the detention time (residence time or theta) in the activated sludge system is most nearly: O 28 hours O 6.5 hours O 168 hours O 53 hours
3. A 100 mL of wastewater sample was drying on a 0.5 g empty dish weight at 104 °C to weight 0.5625 g. Another 100 mL of the same wastewater was first filtered and the filtrate was dried on a 0.5 g dish at 104 °C to weight 0.5325 g. Determine in mg/L the:a) TSb) TSSc) TDSd) VSS assuming it represents 70% of TSS
A wastewater flow of 10,000 m³/d containing 400 mg/L BOD5 is to be treated in a rotating biological contactor (RBC) system. To attain an effluent BOD5 of 20 mg/L (50% soluble), the overall surface loading will be 7.5 kg BOD5/1000 m²-d and the first-stage surface loading will be 45 kg BOD5/1000 m²-d. Determine the minimum total number of standard shafts (9300 m² surface area per shaft) needed for the RBC system.
An industrial wastewater discharged at a flowrate of 1000 m³/d having 220 mg/l initial concentration of total suspended solids (TSS). If this wastewater is to be treated individually by one of the following processes: 1. Primary settling tank which should remove 60% of TSS. 2. Coagulation unit using 40 g ferric chloride (FeCl3) as a coagulant /m²³ of wastewater. The coagulation unit will remove 85% of TSS. Estimate the mass and volume of the sludge generated from each suggested unit. Assume the following sludge specification: Source of sludge Primary settling tank Coagulation tank Specific gravity 1.03 1.05 Moisture content 94% 92%
A CMAS treatment system must be designed for a municipal wastewater and the following operating conditions: • Effluent flow of 0.39 m³/s leaving the primary clarifier Effluent soluble BOD; of 310 mg/L leaving the primary clarifier 20 mg/L of soluble BOD5 allowed in the effluent from the secondary clarifier Negligible suspended solids in the effluent from the secondary clarifier • Volatile suspended solids concentration of 4300 mg/L in the aeration tank • In the laboratory under log-growth conditions, the microorganisms used in the aeration tank can convert 100 g soluble BODS into 55 g VSS • Microorganisms in the CMAS system have a death rate constant of 0.05 d'. Sludge age in the CMAS treatment system will be 4 days (a) Determine the % treatment efficiency for soluble BOD; required in the CMAS system. (b) Determine the required volume of the aeration tank (in m²) and HRT (in h). (c) Determine the food-to-microorganism ratio (in d') and the specific substrate utilization ratio (in d').…
Sketch a typical Streeter-Phelps oxygen-sag curve and state the limitations of the Streeter-Phelps equation shown below: k, Lo -kt D= k2 – k -e (b) Wastewater discharges through an outfall into a slow moving river that has a mean velocity of 3 cm/s. After initial mixing, the dissolved oxygen concentration in the river is 9.5 mg/L, and the temperature is 20°C. The ultimate BOD of the mixed river water is 30 mg/L, the rate constant for BOD at 20°C is 0.48 di and the re-aeration constant at the same temperature is 0.72 d. The saturation concentration of oxygen is 10.2 mg/L at 15°C. i. Estimate the critical time, to, and location, X., with reference to dissolved oxygen concentration. ii. Estimate the minimum dissolved oxygen at the critical location, and comment on the ecological implication of the same.
The wastewater from a synthetic textile manufacturing plant is discharged to a municipal treatment plant for processing with domestic wastewater. The characteristics of the synthetic textile wastewater are 1500 mg/L BOD, 2000 mg/L SS, 30 mg/L nitrogen, and no phosphorus. The characteristics of the domestic wastewater are 200 mg/L BOD, 240 mg/L SS, 35 mg/L nitrogen, and 7 mg/L phosphorus. Find the BOD, SS of the mixture. The ratio of flow rate is domestic/textile = 4/1

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