1.) Sixty grams of FeCl3 reacts with 50.0 grams of H2S. 2 FeCl3 (s) + 3 H2S (g) ---> 6 HCI + Fe2S3 (s) (A) What is the limiting reactant? (B) What is the mass of HCl produced? Molar Masses: 1 mole of FeCl3 = 162.20 grams of FeCl3 1 mole of H2S = 34.09 grams of H2S 1 mole of HC = 36.46 grams of HCl Ratio: 2 mole of FeCl3 = 6 mole of HCI 3 mole of H2S = 6 mole of HCI

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter4: Chemical Reactions
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Problem 4.93P: 4-93 Ammonia is prepared industrially by the reaction of nitrogen and hydrogen according to the...
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1.) Sixty grams of FeCl3 reacts with 50.0 grams of H2S.
2 FeCl3 (s) + 3 H2S (g) ---> 6 HCI + FezS3 (s)
(A) What is the limiting reactant?
(B) What is the mass of HCl produced?
Molar Masses:
1 mole of FeCl3 = 162.20 grams of FeCl3
%3D
1 mole of H2S = 34.09 grams of H2S
%3D
1 mole of HCI = 36.46 grams of HCl
Ratio:
2 mole of FeCl3 = 6 mole of HCl
3 mole of H2S = 6 mole of HCI
Transcribed Image Text:1.) Sixty grams of FeCl3 reacts with 50.0 grams of H2S. 2 FeCl3 (s) + 3 H2S (g) ---> 6 HCI + FezS3 (s) (A) What is the limiting reactant? (B) What is the mass of HCl produced? Molar Masses: 1 mole of FeCl3 = 162.20 grams of FeCl3 %3D 1 mole of H2S = 34.09 grams of H2S %3D 1 mole of HCI = 36.46 grams of HCl Ratio: 2 mole of FeCl3 = 6 mole of HCl 3 mole of H2S = 6 mole of HCI
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